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Nikitich [7]
3 years ago
9

Help me plz it’s hard for me lol

Mathematics
1 answer:
slava [35]3 years ago
3 0

Answer:

36

Step-by-step explanation:

2 *3 sqare root 3 * 12

Solving gives:

6 sqare root 36.

sqare root 36 = 6

2 * 6 * 3

So our answer is 36.

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Given that ∠A and ∠B are supplementary, Daisy conjectured that ∠A≅∠B . Which statement is a counterexample to Daisy's conjecture
Nonamiya [84]

I believe the answer is C. 40 and 140.

8 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
Eduardwww [97]

Hi there! I haven't done math in a while but I do well and I hope this helps. First, we get our radius from our area, which is about 4 inches. From there, I used the volume formula and got the answer closest to C, or 267.95. Thanks, good luck :)

8 0
3 years ago
.......... is the slope zero
Eddi Din [679]

Answer:


Step-by-step explanation:

OK... You have to use this formula: <u>Y2 - Y1</u>

                                                          X2 - X1

  • -2 represents X1
  • 7 represents Y1
  • 2 represents X2
  • -5 represents Y2    

<u>Y2 - Y1</u>

X2 - X1

<u>-5 - 7</u>

2 - - 2

<u>-12</u>

-2

Simplify by dividing both -12 & -2 by 2: <u>-6</u>

                                                                 -1

It's either <u>-6</u> or it's just -6 by itself... Really sorry if I'm wrong...

                -1  




4 0
3 years ago
Read 2 more answers
Do any of you know how to do this
Gre4nikov [31]

Answer:

(x + 5)

Step-by-step explanation:

{x}^{2}  + 8x + 15 \\  {x}^{2}  + 3x + 5x + 15 \\ x(x + 3)5(x + 3) \\ (x + 3)(x + 5) \\ length \:  =  \frac{(x + 3)(x + 5)}{(x + 3)}  \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = (x  + 5)

5 0
2 years ago
Read 2 more answers
Plz help!
beks73 [17]

First, you need to find the derivative of this function.  This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.  

f'(x)=3x^2-3

Now, set this function equal to 0 to find x-values of the relative max and min.

0=3x^2-3

0=3(x^2-1)

0=3(x+1)(x-1)

x=-1, 1

To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each.  We will use -2, 0, 2.

f'(-2)=3(-2)^2-3=3(4)-3=12-3=9

f'(0)=3(0)^2-3=3(0)-3=0-3=-3

f'(2)=3(2)^2=3(4)-3=12-3=9

We examine the sign changes to determine whether it is a max or a min.  If the sign goes from + to -, then it is a maximum.  If it goes from - to +, it is a minimum.  Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.

To determine the values of the relative max and min, plug in the x-values to f(x).

f(-1)=(-1)^3-3(-1)+1=-1+3+1=3

f(1)=(1)^3-3(1)+1=1-3+1=-1

Hope this helps!!

7 0
3 years ago
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