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natali 33 [55]
4 years ago
8

Suppose you had 1.0 mol samples the following gases at STP. If the volume of each of the samples of gas was reduced to one tenth

of its original size and the temperature remained the same, which gas would have the lowest pressure?
A) He
B)Kr
C)N2
D)NO
E)O2

Chemistry
2 answers:
Svetlanka [38]4 years ago
7 0

Answer:

A) He

Explanation:

Hello,

In this case, as the volume is dwindled and the pressure is increased 10 times the initial one, an increase in the non-ideality of the mixture is shown, thus, the least nonideal gas is the helium since it has the weakest intermolecular forces causing its pressure to be the lowest one.

Best regards.

Leokris [45]4 years ago
4 0
A.He
because He 's molecular weight is small than each other

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olchik [2.2K]

Answer:

The answer to your question is   V2 = 1.82 l

Explanation:

Data

Volume 1 = 77 l

Pressure 1 = 18 mmHg

Volume 2 = ?

Pressure 2 = 760 mmHg

Process

Use Boyle's law to solve this problem

                P1V1 = P2V2

-Solve for V2

                 V2 = P1V1/P2

-Substitution

                 V2 = (18 x 77) / 760

-Simplification

                 V2 = 1386 / 760

-Result

                 V2 = 1.82 l

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