Answer:
ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.
Explanation:
Answer:
thx
Explanation:
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A amplitude = 0.50 m and wave-length = 1.0 m
B amplitude = 0.40 m and wave-length = 2.0 m
C amplitude = 0.60 m and wave-length = 2.0 m
Answer:
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Moles of NH3 = mass of NH3/molecular mass of NH3 = 1.7/17= O.1 MOLES.