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Blizzard [7]
3 years ago
8

Hydrofluoric acid (HF) can be prepared according to the following equation:

Chemistry
2 answers:
White raven [17]3 years ago
7 0

Answer:

The Hf is 34.78

Explanation:

first put it to moles with the grams times 1mol/ the atomic mass of the element or compound

Artemon [7]3 years ago
3 0

Given the balanced equation:

( Reaction type : double replacement)

CaF2 + H2SO4 → CaSO4 + 2HFI

We can determine the number of grams prepared from the quantity of 75.0 H2SO4, and 63.0g of CaF2 by converting these grams to moles per substance.

This can be done by evaluating the atomic mass of each element of the substance, and totaling it to find the molecular mass.

For H2SO4 or hydrogen sulfate it's molecular mass is the sum of the quantity of atomic mass per element. H×2 + S×1 + O×4 = ≈1.01×2 + ≈32.06×1 + ≈16×4 = 2.02 + 32.06 + 64 = 98.08 u (Dalton's or Da) or g / mol.

For CaF2 or calcium fluoride, it's molecular mass adds 1 atomic mass of calcium and 2 atomic masses of fluoride due to the number of atoms.

Ca×1 + F×2 = ≈40.07×1 + ≈19×2 = 40.08 + 38 = 78.07 u (Da or Dalton's) or g / mol.

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The two electrons in a helium atom occupy
IRINA_888 [86]

Answer:

the answer is A

Explanation:

4 0
3 years ago
Nitrous oxide (N2O) is used as an anesthetic (laughing gas) and in aerosol cans to produce whipped cream. It is also a potent gr
scZoUnD [109]

Answer:

five half lives

Explanation:

Half-life is the time required for a quantity to reduce to half of its initial value.

How many half lives it would take to reach 3.13% form 100% of it's initial concentration:

100% - 50% : First Half life

50% - 25%: Second Half life

25% - 12.5%: Third Half life

12.5% - 6.25%: Fourth Half life

6.25% - 3.125%: Fifth Half life

This means it would take five half lives to get to 3.125% (≈ 3.13%) of it's original concentration.

3 0
3 years ago
Describe some diff. types of weather that your city or town experience often
harina [27]
Michigan can go from snowing 20° to sunny 60° in less than a day so‍♀️ lately it’s been snowing hard with rain after so now everything is slush
7 0
3 years ago
How many liters of water vapor, at stp, are produced by the combustion of 12.0 g of methane?
erastovalidia [21]
Answer is: 33,6 liters of water vapor.
Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
m(CH₄) = 12 g.
n(CH₄) = m(CH₄) ÷ M(CH₄)
n(CH₄) = 12 g ÷ 16 g/mol = 0,75 mol
from reaction: n(CH₄) : n(H₂O) = 1 : 2
n(H₂O) = 1,5 mol.
V(H₂O) = n(H₂O) · Vm
V(H₂O) = 1,5 mol · 22,4 mol/dm³
V(H₂O) = 33,6 dm³.
8 0
3 years ago
Read 2 more answers
Help would be appreciated t.t
Serhud [2]

Answer:

a) H3PO4 (aq) + 3 KOH (aq) → K3PO4 (aq) + 3 H2O (l)

b)

AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaNO3 (aq)

c)

Ca(OH)2 (s) + 2 H3PO4 (aq) → Ca(H2PO4)2 (s) + 2 H2O (l)

d)

2 KI (aq) + Pb(NO3)2 (aq) → 2 KNO3 (aq) + PbI2 (s)

e)

3 H2SO4 (aq) + 2 Al(OH)3 (s) → 6 H2O (l) + Al2(SO4)3 (aq)

All balanced equation for each reaction!!

5 0
3 years ago
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