Answer:
five half lives
Explanation:
Half-life is the time required for a quantity to reduce to half of its initial value.
How many half lives it would take to reach 3.13% form 100% of it's initial concentration:
100% - 50% : First Half life
50% - 25%: Second Half life
25% - 12.5%: Third Half life
12.5% - 6.25%: Fourth Half life
6.25% - 3.125%: Fifth Half life
This means it would take five half lives to get to 3.125% (≈ 3.13%) of it's original concentration.
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Answer is: 33,6 liters of water vapor.
Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
m(CH₄) = 12 g.
n(CH₄) = m(CH₄) ÷ M(CH₄)
n(CH₄) = 12 g ÷ 16 g/mol = 0,75 mol
from reaction: n(CH₄) : n(H₂O) = 1 : 2
n(H₂O) = 1,5 mol.
V(H₂O) = n(H₂O) · Vm
V(H₂O) = 1,5 mol · 22,4 mol/dm³
V(H₂O) = 33,6 dm³.
Answer:
a) H3PO4 (aq) + 3 KOH (aq) → K3PO4 (aq) + 3 H2O (l)
b)
AgNO3 (aq) + NaCl (aq) → AgCl (s) + NaNO3 (aq)
c)
Ca(OH)2 (s) + 2 H3PO4 (aq) → Ca(H2PO4)2 (s) + 2 H2O (l)
d)
2 KI (aq) + Pb(NO3)2 (aq) → 2 KNO3 (aq) + PbI2 (s)
e)
3 H2SO4 (aq) + 2 Al(OH)3 (s) → 6 H2O (l) + Al2(SO4)3 (aq)
All balanced equation for each reaction!!