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wlad13 [49]
3 years ago
12

La siguiente gráfica representa la velocidad como función del tiempo para dos carros que parten simultáneamente desde el mismo p

unto de una carretera recta
Physics
1 answer:
xenn [34]3 years ago
6 0
Шада и я тебя понимаю с чего начать с того ни другого человека дал в долг у меня в здоровье
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A wave with an amplitude of 9.3 mm is traveling along a string whose linear mass density is 230 g/m and whose tension is 65 N. I
dsp73

Answer:

The rate of transfer of energy is equal to 23.76W or 23.76J/s as may be required both forms are correct. The physical quantities needed to calculate the rate of energy transfer are the linear mass density or mass per unit length, tension force, amplitude, angular frequency( which is equal to 2pi •f )

Explanation:

The required quantity is the average power or average rate of energy transfer which differs from the maximum or instantaneous rate of energy transfer. The calculation steps to the answer above can be found in the attachment below. Should the requested quantity be the instantaneous quantity the answer will be 2 x Pav which equals 47.52W or 47.52J/s.

3 0
3 years ago
you have two pendulums with cords that are exactly the same length. one is on earth (with an acceleration due to gravity of 9.81
olga55 [171]
From  T = 2π√(l/g).

Since the lengths are the same, so that is a constant.

T α 1/√g

So the period T is inversely proportional to the square root of gravity g.

So the one with a bigger gravity g would have a shorter period

and

the one with smaller gravity g would have a longer period.

Therefore the period on the Moon with gravity of 1.63 m/s² would be longer period than that on the Earth with gravity of 9.81 m/s² 
8 0
3 years ago
Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?
ohaa [14]

Answer:

C. 212,000 years

Explanation:

believe me it's correct.....and you're welcome :)

4 0
3 years ago
While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83
allochka39001 [22]

To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

\beta_{dB} = 10log_{10}\frac{I}{I_0}

Where,

\beta_{dB}= Sound intensity level in decibels

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB

So:

10log_{10}(\frac{32I}{I_0}) = 83

10log(\frac{I}{I_0})+10log(32) = 83

10log(\frac{I}{I_0})= 83-10log(32)

10log(\frac{I}{I_0})= 67.948dB

Therefore the sound intensity due to one person is 67.948dB

8 0
3 years ago
When you lift an object, you add the energy of lifting to the object.<br> Tor F
PtichkaEL [24]

It's true, when we lift an object we add energy to it.

because, when we lift an object by applying force , the object attains a height and hence the energy gets stored in it, in the form gravitational potential energy .

6 0
3 years ago
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