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user100 [1]
4 years ago
10

17. When 1 mol of the following substances react completely with oxygen, the

Chemistry
2 answers:
Len [333]4 years ago
3 0
I would say Na. Oxygen has 2 valence electrons and when reacting with other molecules, the ones with the fullest or emptiest shells will react the least. Both H2 and Na are in the Alkali Metals in the first row, but since H2 has 2 molecules, it would use more oxygen than Ana
goldenfox [79]4 years ago
3 0

Answer:

Option A. Na

Explanation:

Let us generate a balanced equation for the reaction of O2 with the individual elements. This is illustrated below:

1. 4Na + O2 —> 2Na2O

From the equation,

4moles of Na comsumed 1mole of O2.

Therefore, 1mole of Na will comsume = 1/4 = 0.25mol of O2.

2. 2Ca + O2 —> 2CaO

From the equation,

2moles of Ca consumed 1 mole of O2.

Therefore, 1mole of Ca will consume = 1/2 = 0.5mole of O2

3. 4Al + 3O2 —> 2Al2O3

From the equation,

4moles of Al consumed 3moles of O2.

Therefore, 1mole of Al will consume = 3/4 = 0.75mol of O2

4. 2H2 + O2 —> 2H2O

From the equation,

2moles of H2 consumed 1mole of O2.

Therefore, 1mole of H2 will consume = 1/2 = 0.5mole of O2

The following data were obtained from the above calculations:

1mole of Na requires 0.25mol of O2

1mole of Ca requires 0.5mole of O2

1mole of Al requires 0.75mol of O2

1mole of H2 requires 0.5mole of O2

From the above, we see clearly that 1mole of Na consumes the least amount of O2

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3 years ago
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What is the molar mass of a gas if a flask with a volume of 3. 16 l contains 9. 33 grams of the gas at 32. 0°c and 1. 00 atm?
Serhud [2]

The molar mass of a gas if a flask with a volume of 3. 16 L contains 9. 33 grams of the gas at 32. 0°C and 1. 00 atm is  1.17g/mol

Calculation ,

In this question we have to fist find the number of moles of gas by using ideal gas equation and from the help of number of moles we can determine molar mass.

According to ideal gas equation which is also known as ideal law ,

PV = nRT                ...( i )

where P is the pressure of the gas = 1 atm

V is the volume of the gas in the flask with volume =  3. 16 L

R is the universal gas constant = 0.082 atm L/K mol

T is the temperature = 32. 0°C = 32 + 273 = 305 K

n is the number of moles = ?

Putting the value of Pressure P , volume V , temperature T , number of moles n and universal gas constant R in the equation (i) we get ,

1 atm ×3. 16 L = n× 0.082 atm L/K mol ×305 K

n = 1 atm ×3. 16 L / 0.082 atm L/K mol × 305 K = 0.126 mole

number of mole of a gas  = 0.126 mole = given mass/ molar mass

molar mass  = number of moles × Given mass =  0.126 × 9. 33 = 1.17g/mol

Learn about flask

brainly.com/question/14161066

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7 0
1 year ago
18.2L of gas at 95°C and 760 torr is placed in a 15L container at 80 degrees * C ; what is the new pressure ?
romanna [79]

Answer:

884.56 torr

Explanation:

Formula: \frac{P_{1}V_{1} }{T_{1}} = \frac{P_{2}V_{2} }{T_{2}}

P = Pressure

V = Volume

T = Temperature in kelvin (Celsius + 273.15)

\frac{(760)(18.2) }{368.15} = \frac{P(15) }{353.15}

P = \frac{(760)(18.2)(353.15) }{(368.15)(15)}

P = 884.56169

4 0
3 years ago
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
3 years ago
When molten rock undergoes crystallization above ground, what type of rock results?
Alika [10]
Your answer should be:
<span>Extrusive igneous rock</span>
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3 years ago
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