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user100 [1]
3 years ago
10

17. When 1 mol of the following substances react completely with oxygen, the

Chemistry
2 answers:
Len [333]3 years ago
3 0
I would say Na. Oxygen has 2 valence electrons and when reacting with other molecules, the ones with the fullest or emptiest shells will react the least. Both H2 and Na are in the Alkali Metals in the first row, but since H2 has 2 molecules, it would use more oxygen than Ana
goldenfox [79]3 years ago
3 0

Answer:

Option A. Na

Explanation:

Let us generate a balanced equation for the reaction of O2 with the individual elements. This is illustrated below:

1. 4Na + O2 —> 2Na2O

From the equation,

4moles of Na comsumed 1mole of O2.

Therefore, 1mole of Na will comsume = 1/4 = 0.25mol of O2.

2. 2Ca + O2 —> 2CaO

From the equation,

2moles of Ca consumed 1 mole of O2.

Therefore, 1mole of Ca will consume = 1/2 = 0.5mole of O2

3. 4Al + 3O2 —> 2Al2O3

From the equation,

4moles of Al consumed 3moles of O2.

Therefore, 1mole of Al will consume = 3/4 = 0.75mol of O2

4. 2H2 + O2 —> 2H2O

From the equation,

2moles of H2 consumed 1mole of O2.

Therefore, 1mole of H2 will consume = 1/2 = 0.5mole of O2

The following data were obtained from the above calculations:

1mole of Na requires 0.25mol of O2

1mole of Ca requires 0.5mole of O2

1mole of Al requires 0.75mol of O2

1mole of H2 requires 0.5mole of O2

From the above, we see clearly that 1mole of Na consumes the least amount of O2

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How many ml of a 0.50m solution of hno3 solution are needed to make 500 ml of 0.15m hno3
Anna71 [15]

Answer:

150.0 mL.

Explanation:

  • It is known that the no. of millimoles of HNO₃ before dilution = the no. of millimoles of HNO₃ after dilution.

∵ (MV) before dilution = (MV) after dilution.

<em>∴ V before dilution = (MV) after dilution / M before dilution</em> = (0.15 M)(500.0 mL)/(0.50 M) = <em>150.0 mL.</em>

7 0
3 years ago
What happens to concrete when it's no longer needed
Sveta_85 [38]
Did you mean when it is a liquid?
8 0
2 years ago
could you please explain operations with scientific notation using this example. 5 × 10³ + 4.3 × 10⁴ i dont understand how to so
TEA [102]

Explanation:

The scientific notation:

a\times10^k

where

1\leq a and k is integer.

We have the example:

(5\times10^3)+(4.3\times10^4)

You can write the numbers in a "normal" form:

5\times10^3=5\times1000=5000\\\\4.3\times10^4=4.3\times10000=43000

Make the sum:

5000+43000=48000

And next write it in the scientific notation:

48000=4\underbrace{8000}_{\leftarrow4}=4.8000\times10000=4.8\times10^4

<h3>Other method:</h3>

You can add numbers in scientific notation if the power of tens in both number is the same.

Therefore you must convert the first number:

5\times10^3=0.5\times10\times10^3=0.5\times10^4

Now, you can make the sum:

(5\times10^3)+(4.3\times10^4)=0.5\times10^4+4.3\times10^4=(0.5+4.3)\times10^4=4.8\times10^4

4 0
3 years ago
Write the condensed nd structural formulas as well as the names for all isomers of C3H5Cl3.
Sergio039 [100]

Answer:

1) 1,1,1-trichloropropane

2) 1,1,2-trichloropropane

3) 1,2,2-trichloropropane

4) 1,2,3-trichloropropane

Explanation:

For this question, we must remember that isomers are molecules that have the <em>same formula but different structure</em>s. For the formula C_3H_5Cl_3 we can draw a <u>linear chain of three carbons</u> and change the position of the chlorine atoms in the carbon chain.

With this in mind, if we put all the chlorine atoms on the same carbon we will get <u>1,1,1-trichloropropane</u>. If we change an atom from chlorine to carbon 2 we will obtain <u>1,1,2-trichloropropane</u>. If we move another chlorine atom to carbon two we will get <u>1,2,2-trichloropropane</u>. Finally, if we put a chlorine atom in each carbon we will obtain <u>1,2,3-trichloropropane</u>.

See figure one for further explanations

I hope it helps!

4 0
3 years ago
Which substances corrode copper?​
DiKsa [7]
The presence of oxidizing acids; heavy-metal salts, sulfur, and ammonia; and a number of sulfur and ammonia compounds can cause corrosion to set in. Water that comes from a well is much more likely to contain these materials and put copper lines in jeopardy—but it can occur in the civic water system as well.

Copper corrodes at insignificant rates when used in areas with unpolluted air, non-oxidizing acids, and water. However, it happens more rapidly with the presence of road salt, ammonia, sulfur, oxidizing acids

Acidic substances react with the surface of copper, causing it to tarnish and corrode almost instantly. This corrosion is highly soluble, leading to the presence of toxic copper salts in the food. This is why it is not recommended to use copper vessels for foods high in acidity, such as milk, wine, or vinegar.
4 0
2 years ago
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