Answer:
37.1 g of Arsenic
Explanation:
2.98 x 10^21 atoms of Arsenic x 74.92g/6.02 x 10^23
= 223.26 x 10^21/6.02 x 10^23
= 2.2326 x 10^23/6.02 x 10^23
= 37.1 g of Arsenic
Answer:
Explanation:
<u>1) Data:</u>
a) mass of solute = ?
b) volume of solution = 1.25 liter
c) M = 2.92 mol/liter
d) solute NaOH
<u>2) Formulae:</u>
<u />
a) Molarity, M = number of moles of solute / volume of solution in liters
b) mass in grams = molar mass × number of moles
<u>3) Solution:</u>
a) <u>Calculate number of moles of solute</u>:
- M = number of moles of solute / volume of solution in liters
⇒ number of moles of solute = M × volume of solution in liters
⇒ number of moles of solute = 2.92 mol/liter × 1.25 liter = 3.65 mol
b) <u>Molar mass of NaOH = 39.997 g/mol </u>(you can take this number from internet or calculate it using the atomic masses of Na, O, and H).
c) <u>Calculate the mass of solute:</u>
- mass in grams = molar mass × number of moles = 39.997 g/mol × 3.65 mol = 145.98905 g = 146. g
The answer must be reported with 3 significant figures, so it is 146. g.
The larger the piece the longer it will take to break down. This is because it has more mass that needs to be broken down.
Answer:
1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).
2. The difference in pH values is 4.95.
Explanation:
1. The pH of a compound can be found using the following equation:
First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.
<u>Trimethyl ammonium</u>:
We can calculate [H₃O⁺] using the Ka as follows:
(CH₃)₃NH⁺ + H₂O → (CH₃)₃N + H₃O⁺
1.0 - x x x
By solving the above equation for x we have:
x = 0.097 = [H₃O⁺]
<u>Phenol</u>:
C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺
1.0 - x x x
Solving the above equation for x we have:
x = 9.96x10⁻⁶ = [H₃O⁺]
Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.
2. The difference in pH values for the two acids is:
Therefore, the difference in pH values is 4.95.
I hope it helps you!
Answer:
Kp and Kc are 0.01266 and 145.17, respectively.
Explanation:
Please check document attached.