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jekas [21]
4 years ago
5

In the simulation, open the Custom mode. The beaker will be filled to the 0.50 L mark with a neutral solution. Set the pH to 2.8

5 by using the green arrows adjacent to the pH value indicated on the probe in the solution. Once you adjust the pH, note the corresponding OH? ion concentration in M as given in the graphic on the left side of the simulation. Make sure to select the option "Concentration (mol/L)" above the graphic. Select on the Logarithmic scale below the graphic.
Find the pOH of the solution.
Express your answer numerically to two decimal places.
Chemistry
1 answer:
REY [17]4 years ago
3 0

ur mom ur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur mom

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DanielleElmas [232]
The ratio of atoms of potassium to ratio of atoms of oxygen is 2:1
5 0
3 years ago
Which condition must be met in order for an equation to be balanced? The elements in the reactants are the same as the elements
Nookie1986 [14]

Answer:

There must be an equal amount of each element on both sides of the equation.

Hope this helps

good luck

8 0
3 years ago
Read 2 more answers
A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4      = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

7 0
3 years ago
Imagine that one tree outside your home looks unhealthy, although all the other trees seem healthy and strong. Describe how you
Westkost [7]

Answer:

Hypothesis---experiments----results----conclusion.

Explanation:

First we make a hypothesis means a statement about why the tree looks unhealthy. In this segment of scientific method we have to test the hypothesis through experimentation. After that we have to take the readings of various parts of the tree and analyze the data to find out the problem. In the next step, we have to made the results on the basis of the data that is obtained. In the last we have to write the conclusion of the analysis and see the hypothesis.

5 0
3 years ago
What is the molality of a solution of 12.9 g of fructose (C6H12O6) in 31.0 g of water?
jasenka [17]

Answer:

2.31 m C₆H₁₂O₆

Explanation:

Hope this helps

8 0
3 years ago
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