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jekas [21]
3 years ago
5

In the simulation, open the Custom mode. The beaker will be filled to the 0.50 L mark with a neutral solution. Set the pH to 2.8

5 by using the green arrows adjacent to the pH value indicated on the probe in the solution. Once you adjust the pH, note the corresponding OH? ion concentration in M as given in the graphic on the left side of the simulation. Make sure to select the option "Concentration (mol/L)" above the graphic. Select on the Logarithmic scale below the graphic.
Find the pOH of the solution.
Express your answer numerically to two decimal places.
Chemistry
1 answer:
REY [17]3 years ago
3 0

ur mom ur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur momur mom

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Calculate the total pressure in a 10.0 liter flask at 27°C of a sample of gas that contains 6.0 grams of hydrogen, 15.2 grams of
motikmotik

Answer:

The total pressure is 27.8 atm

Explanation:

From the ideal gas equation,

PV = nRT

P (total pressure) = nRT/V

n (total moles of gases) = (6/1 moles of hydrogen) + (15.2/14 moles of nitrogen) + (16.8/4 moles of helium) = 6+1.1+4.2 = 11.3 moles

R = 0.082057L.atm/gmol.K, T = 27°C = 27+273K = 300K, V = 10L

P = 11.3×0.082057×300/10 = 27.8 atm

7 0
3 years ago
Lucia is playing with magnetic toy vehicles. She has two identical toy vehicles (purple and pink) that start on opposite sides o
pentagon [3]

Answer:

The potential energy of both toy vehicles (purple and pink) decreased. Since the pink toy was moved closer to the magnet, it will have less potential energy because of the short distance it will take to travel to the magnet. Although the purple toy is now closer to the magnet, it is still pretty far and will have a somewhat big potential energy when traveling to the magnet.

Explanation:

Hey, I'm in middle school and I had the same question for a science test, I'm not sure if I am correct but this is what I have.

3 0
3 years ago
Read 2 more answers
What charge is there on a lithium ion?
gogolik [260]
Lithium is in the Alkali Metal group or 1A column. The atoms in this group form ions with a 1+ charge. Lithium ion’s charge is 1+.
3 0
3 years ago
Read 2 more answers
Find the weight of HNO_3 present in 20ml, 0.30 N
yanalaym [24]

Answer:

mass of HNO₃ = 0.378 g

Explanation:

Normality = Molarity * number of equivalents

Molarity = Normality/number of equivalents

normality of HNO₃ = 0.30 N, Volume = 20 mL

HNO₃ ionizes in the following way:

HNO₃(aq) ----> H⁺ + NO₃⁻

Therefore, number of equivalents for HNO₃ is 1

molarity of HNO₃ = 0.30/1 =0.30 mol/dm³

Using the formula, molarity = number of moles/volume in liters

number of moles = molarity * volume

Number of moles of HNO₃ = 0.30 mol/dm³ * 20ml * 1 dm³ /1000 mL

number of moles = 0.006 moles

From the formula, mass = number of moles * molar mass

molar mass of HNO₃ = 63.0 g/mol

mass = 0.006 * 63

mass of HNO₃ = 0.378 g

6 0
3 years ago
Which of the following has a mass of 10.0 g?
Serjik [45]

Answer:

a.  0.119mol Kr

Explanation:

To solve this problem, we must understand that;

     Mass  = number of moles x molar mass

Molar mass of Kr  = 83.3g/mol

                        Ar = 40g/mol

                        He = 4g/mol

                        Ne = 20.18g/mol

a0.119 mol Kr               mass  = 0.119 x 83.3 = 9.9g

b 0.400 mol Ar             mass  = 0.4 x 40  = 16g

C 1.25 mol He               mass  = 1.25 x 4  = 5g

d 2.02 mol Ne              mass  = 2.02 x 20.18  = 40.8

Krypton is the answer

5 0
3 years ago
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