<u>Let's take this problem step-by-step</u>:
<u>Let's first set up some variables</u>:
- c: # of children
- a: # of adults
<u>Let's examine the information given:</u>
- Elevator can hold a maximum of 1500 pounds
⇒ average child is 75 pounds
⇒ average adult is 150 pounds
⇒<em> therefore</em>: 
- Elevator can fit no more than 14 people
⇒ <em>therefore</em>: 
<u>Let's graph the equations</u>:

⇒ look at the image attached
<u>The point at which the two graphs intersect:</u>
⇒ <em>is the solution that represents the amount of children and adults and </em>
<em> their combine weight</em>
<em />
<u><em>With the horizontal axis being the # of children and vertical axis being the # of adults</em></u><em>:</em>
<em> ⇒ the </em><em>solution is 8 children and 6 adults</em>
<em></em>
<u>Answer: 8 children and 6 adults</u>
<u></u>
Hope that helped!
<em />
Answer:
25.12
Step-by-step explanation:
The formula of the circumference of a circle is: C = 2(pi)(r)
Plug in 3.14 for pi and 4 for the radius.
C = 2(3.14)(4)
Multiply.
C = 25.12
This is the concept of applications of polynomial equations. Given that the height of the ball is modeled by the function:
h(t)=16t^2-64t
the maximum height will be calculated as follows;
h(t)=16t(t-4)
therefore:
t=0 or t=4
h(4)=-64(4)+16(4^2)
=0
Answer:
I think that if u times it i will be 80 s and 320 f
Step-by-step explanation:
At first glance, it seems like a good estimate; big numbers make bigger number.
But, this is multiplication, which means big numbers will make an extraordinarily big number, in proportion to the numbers themselves.
If you round 31 3/4 up to 32, you can multiply that by 50. To make the estimate easier, multiply 50 by 2,
50 x 2 = 100
Take the zeros off 50 and 30 to make this a bit simpler, and multiply 5 by 3,
5 x 3 = 15
Add each of the zeros you took off to the 15 to make 1500 (1 zero was taken off 50, and 1 off of 30),
And then add 1500 to that other 100
1500 + 100 = 1600
A good estimate for 50 x 31 3/4 would be 1600, not 800.
Therefore,
No. Brenda's estimate of 800 is NOT a good estimate.