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Schach [20]
4 years ago
6

When using the magnification equation, a value greater than 1 as the solution for M indicates that the image ? is larger than th

e object. smaller than the object. real. virtual
THE RIGHT ANSWER IS A LARGE THAN THE OBJECT
Physics
2 answers:
Nadusha1986 [10]4 years ago
7 0
M= Height of image/height of the object

If, M>1, then height of image>height of object.

And therefore, image is larger than the object.
Ksenya-84 [330]4 years ago
6 0

Answer: A) larger than the object.

Explanation:

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What is the relative energy expense of galloping rather than trotting at 3.5 m/s?
labwork [276]

Answer: Trotting uses only 75 percent of the energy as galloping

Explanation: Trotting is only 300 J/m, whereas galloping is roughly 400 J/m

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3 years ago
What is the function of the commutator in a DC motor? to spin the magnet to change direct current into alternating current to ch
Anestetic [448]
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4 0
3 years ago
what is the specific heat capacity of silver metal if 55.00g of the absored 47.3 calories of heat and temperature rise 15.°c​
igor_vitrenko [27]

Answer:

0.240 J/(g^{\circ}C)

Explanation:

When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by \Delta T according to the equation

Q=mC_s \Delta T

where

C_s is the specific heat capacity of the substance

In this problem, we have:

m = 55.0 g is the mass of the sample of silver

Q = 47.3 \cdot 4.184 = 197.9 J is the amount of energy supplied to the sample

\Delta T = 15^{\circ}C is the change in temperature of the sample

Solving the equation for C_s, we find the specific heat capacity of silver:

C_s = \frac{Q}{m \Delta T}=\frac{197.9}{(55.0)(15)}=0.240 J/(g^{\circ}C)

3 0
4 years ago
If the water measures -5 feet at low tide and 3ft at high tide what is the tidal range ​
Alex

Answer:

8 feet

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8 0
3 years ago
dos contenedores de objetos tienen 30 y 40 kg de masa respectivamente y están sobre una superficie horizontal sin rozamiento una
Dmitry_Shevchenko [17]

Answer:

The acceleration of each mass is the same, and approximately equal to 1.43\,\,\frac{m}{s^2}

Explanation:

Notice that the mass of the whole system is: 30 kg + 40 kg = 70 kg

If we use a net force of 100 N on the combined system, we can find the acceleration imparted to the masses via Newton's second law:

F_{net}= M\,*\,a\\100\,\,N = 70\,\,kg * a\\a = \frac{100}{70} \,\frac{m}{s^2} \\a\approx 1.43\,\frac{m}{s^2}

4 0
3 years ago
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