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sertanlavr [38]
3 years ago
7

A seamount is an isolated land mass rising from the ocean floor. a. True b. False

Physics
1 answer:
iris [78.8K]3 years ago
7 0
The answer is A, True.
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How does reflection differ from refraction and diffraction?
Otrada [13]
Reflection, i<span>t is the phenomena of getting back the light you've shown from a light source with the same angle. r</span>efraction, <span>It is the phenomena of bending of light when it changes it medium. This </span>can<span> rarer to denser or denser to rarer. d</span>iffraction,<span> It is the phenomena of bending of light near the edges of the object. hope this helps

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5 0
3 years ago
If I work out rotational energy to be 102.2J which equals kg.M/s^2, and I hadn't factored time into it, would that be Joules per
Marina CMI [18]

Answer:

0.057 joules is needed to create the total rotational energy each second.

Explanation:

The energy rate is the ratio of total energy to time, which coincides with the definition of power at constant rate:

\dot W = \frac{\Delta E}{\Delta t}

\dot W = \frac{102.2\,J}{\left(30\,min\right)\cdot \left(60\,\frac{s}{min} \right)}

\dot W = 0.057\,\frac{J}{s}

\dot W = 0.057\,W

0.057 joules is needed to create the total rotational energy each second.

7 0
3 years ago
What are the first and second object in a gravitational field
vodka [1.7K]

downward force then reaction if you mean what forces

3 0
3 years ago
ОТВЕТЬТЕ !!!!СРОЧНО!!!
FromTheMoon [43]

Answer:

ответ 1.25 × 10‐³ и вот ваш ответ

8 0
3 years ago
Suppose that the dipole moment associated with an iron atom of an iron bar is 2.8 × 10-23 J/T. Assume that all the atoms in the
masya89 [10]

To solve this exercise it is necessary to apply the equations related to the magnetic moment, that is, the amount of force that an image can exert on the electric currents and the torque that a magnetic field exerts on them.

The diple moment associated with an iron bar is given by,

\mu = \alpha *N

Where,

\alpha = Dipole momento associated with an Atom

N = Number of atoms

\alpha y previously given in the problem and its value is 2.8*10^{-23}J/T

L = 5.8cm = 5.8*10^{-2}m

A = 1.5cm^2 = 1.5*10^{-4}m^2

The number of the atoms N, can be calculated as,

N = \frac{\rho AL}{M_{mass}}*A_n

Where

\rho = Density

M_{mass} = Molar Mass

A = Area

L = Length

A_n =Avogadro number

N = \frac{(7.9g/cm^3)(1.5cm)(5.8cm^2)}{55.9g/mol}(6.022*10^{23}atoms/mol)

N = 7.4041*10^{23}atoms

Then applying the equation about the dipole moment associated with an iron bar we have,

\mu = \alpha *N

\mu = (2.8*10^{-23})*(7.4041*10^{23})

\mu = 20.72Am^2

PART B) With the dipole moment we can now calculate the Torque in the system, which is

\tau = \mu B sin(90)

\tau = (20.72)(2.2)

\tau = 45.584N.m

<em>Note: The angle generated is perpendicular, so it takes 90 ° for the calculation made.</em>

3 0
3 years ago
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