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3 years ago

Gravity is a force that helps to hold the universe together.true or false

Physics

2 answers:

Valentin [98]3 years ago

7 0

Yes, this is a true statement.

gravity is so important.

Pie3 years ago

5 0

Answer:

True

Explanation:

Gravity is a force that helps to hold the universe together. The statement is true. The gravitational force is always attractive in nature. It depends on the masses and the distance between them. Mathematically, it is given by :

$F=G\dfrac{m_1m_2}{d^2}$

Where

G = universal gravitational constant

m₁ and m₂ are masses

d is the distance between them

Gravity is responsible to hold the planets in an orbit around the sun. Ocean tides are also caused due to gravitational pull of the moon. If gravity is not present in the universe then there would be no moon, no stars etc.

Hence, the given statement is true.

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If a biker starts at rest and accelerates to 15 m/s in 7.5 seconds, what is his<br> acceleration? *

sergeinik [125]

Answer:

2 m/s^2

Explanation:

from the question

v=15 m/s

t=7.5

a=?

from the first equation of motion

v=u+at

where,

v=final velocity

u=initial velocity

a=acceleration

t=time

from the question (u) will be zero because the body started at rest

v=u+at

15=(0)+a×7.5

15=7.5a

a=15/7.5

a=2 m/s^2

6 0

3 years ago

A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori

marshall27 [118]

Answer:

$K_2=6.4J$

Explanation:

According to the principle of conservation of momentum, we have:

$\Delta p=0\\p_i=p_f\\m_1v_1_i +m_2v_2_i=m_1v_1_f+m_2v_2_f$

Here 1 is for the bullet and 2 is for the block. Since the block is initially at rest $v_i_2=0$ . Solving for $v_2_f$ and replacing the given values:

$v_2_f=\frac{m_1(v_1_i-v_1_f)}{m_2}\\v_2_f=\frac{10*10^{-3}kg(1.8\frac{km}{s}-1\frac{km}{s})}{5kg}\\v_2_f=0.0016\frac{km}{s}*\frac{1000m}{1km}=1.6\frac{m}{s}$

The kinetic energy of the block is given by:

$K_2=\frac{m_2(v_f_2)^2}{2}\\K_2=\frac{5kg(1.6\frac{m}{s})^2}{2}\\K_2=6.4J$

3 0

3 years ago

Write an expression to evaluate the relative error in g (given that g= 2h/t^2) in terms of h,Δh,t,Δt

EleoNora [17]

An expression which can be used to evaluate the relative error in g (in terms of h, Δh, t, and Δt) is: $\delta = \frac{t^2(h\;+\Delta \;h) }{h(t\;+\;\Delta t)^2} - 1$

<h3>What is relative error?</h3>

Relative error can be defined as a measure of the ratio of an absolute (real) value of a measurement to an expected (theoretical) value. Also, it's independent of the magnitude of its values.

<h3>How to evaluate the relative error in g?</h3>

In order to write this expression, we would divide the absolute (real) value by the expected (theoretical) value as follows:

$\delta = \frac{g(h\;+\;\Delta h,t \;+ \;\Delta t) - \;g(h,t)}{g(h,t)} \\\\\delta = \frac{g(h\;+\;\Delta h,t \;+ \;\Delta t) }{g(h,t)} - 1\\\\\delta = \frac{t^2(h\;+\Delta \;h) }{h(t\;+\;\Delta t)^2} - 1$

<u>Note:</u> g = 2h/t²

Read more on relative error here: brainly.com/question/13370015

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6 0

2 years ago

A 47 kg child on a 1.5 m long swing is released 5 from rest when the swing supports make an angle of 22 ◦ with the vertical. the

nasty-shy [4]

I dont know what the answer will be

5 0

3 years ago

Explain how the pressure of the ice cube on the ground changes when it melts

Yuliya22 [10]

Answer:

Explanation: Andre Ampere

5 0

3 years ago