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Arada [10]
3 years ago
6

Ben and Jerry, arch rivals, decide to have a weight lifting contest during PE. Ready, set, go! Ben and Jerry both lift a 250 kg

barbell 10 times over their heads. They are approximately the same height and lift the barbell the same distance in the air. It takes Ben 5 seconds to complete 10 lifts; it takes Jerry 25 seconds to complete his 10 lifts. Which statement is MOST accurate regarding the weightlifting contest? A) Ben did more work than Jerry. B) Ben has more power than Jerry. C) Ben and Jerry have the same power. D) Ben does more work and is more powerful than Jerry.
Physics
2 answers:
Sidana [21]3 years ago
7 0

The answer is B. Your welcome.

B    ) STILL CHILL

cluponka [151]3 years ago
7 0

Answer:

B) Ben has more power than Jerry.

Explanation:

Here work done to lift the mass to the certain height is given as

W = mgh

now given that Ben and Jerry both lift the mass to the same height 10 times

so here work done by Ben and Jerry must be same.

now we know that power is defined as rate of work done

P = \frac{W}{t}

now we know from above formula that it took less time by Ben as he lift the mass 10 times in 5 seconds while Jerry took 25 seconds to lift the mass 10 times.

So here power by Ben will be more than Jerry as is took lesser time to complete the task of 10 times lift of mass

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Answer:

Your answer is the following...

(b)"Many valence electrons are shared between the atoms"

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3 years ago
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ira [324]
According to Newton's 2nd law of motion:
F = m * a where F is the force applied in Newtons, m is the mass of the object in kg, and a is the acceleration of the object in m/s^{2}.
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Is this circuit parallel or inseries ​
muminat

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2 years ago
(b) Fig. 1.1 shows two airports A and C. north SE с sea land क WE not to scale Fig. 1.1 An aircraft flies due north from A for a
GalinKa [24]

The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:

  • The distance to go between airports A and C  is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.

In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C

Let's use the Pythagoras theorem to find the distance traveled

               R = Ra x² + y²

               R =   10³

               R = 373.6 10³ m

They indicate the average speed for which we can use the uniform motion ratio

               v = \frac{\Delta y }{t}

                t = \frac{\Delta y}{v}

They ask for the time in in from airport A to B, we calculate

                t = 360 10 ^ 3/170

                t = 2.117 10³ s

In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:

  • The distance to go between airports A and C B is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Learn more here: brainly.com/question/15074838

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