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Arada [10]
3 years ago
6

Ben and Jerry, arch rivals, decide to have a weight lifting contest during PE. Ready, set, go! Ben and Jerry both lift a 250 kg

barbell 10 times over their heads. They are approximately the same height and lift the barbell the same distance in the air. It takes Ben 5 seconds to complete 10 lifts; it takes Jerry 25 seconds to complete his 10 lifts. Which statement is MOST accurate regarding the weightlifting contest? A) Ben did more work than Jerry. B) Ben has more power than Jerry. C) Ben and Jerry have the same power. D) Ben does more work and is more powerful than Jerry.
Physics
2 answers:
Sidana [21]3 years ago
7 0

The answer is B. Your welcome.

B    ) STILL CHILL

cluponka [151]3 years ago
7 0

Answer:

B) Ben has more power than Jerry.

Explanation:

Here work done to lift the mass to the certain height is given as

W = mgh

now given that Ben and Jerry both lift the mass to the same height 10 times

so here work done by Ben and Jerry must be same.

now we know that power is defined as rate of work done

P = \frac{W}{t}

now we know from above formula that it took less time by Ben as he lift the mass 10 times in 5 seconds while Jerry took 25 seconds to lift the mass 10 times.

So here power by Ben will be more than Jerry as is took lesser time to complete the task of 10 times lift of mass

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The third one! :) Hope you live up to what ya promised man lol.
6 0
4 years ago
The critical angle for water is 49°. If a ray of light
Sonja [21]

Answer:

Snell's Law states

Ni sin i = Nr sin r

Judging from the question the source of the ray is in the water (directed up)

or NI = 1 / sin 49      Ni = 1.325 deg     the critical angle

From inside the pond:

Nr = 1.325 * sin 45 / 1 = 94 deg  

So refraction can occur  outside the pond and you do not have total internal refection.

 

3 0
3 years ago
there is a skier at the top of the ski slope the skier has potential energy what gives the skier her potential energy
scoundrel [369]

Her height on the mountain gives her the PE that she has.

She got it from the work that some person or machine did to lift her up there.

3 0
3 years ago
A sound wave with a waveenght of 2.5 meters traves 660 meters in 2 seconds calculate the frequemcy of the wave to cacuation the
finlep [7]

The frequency of the wave is 132 Hz

Explanation:

To calculate the speed of the wave, we can use the following formula:

v = \frac{d}{t}

where

d is the distance travelled by the wave

t is the time elapsed

For the sound wave in this problem, we have:

d = 660 m is the distance travelled

t = 2 s is the time interval considered

Substituting and solving for v, we find the speed of the sound wave:

v=\frac{660}{2}=330 m/s

Now we can calculate the frequency of the wave by using the wave equation:

v=f\lambda

where

v = 330 m/s is the speed of the wave

\lambda=2.5 m is the wavelength

f is the frequency

Solving for f, we find:

f=\frac{v}{\lambda}=\frac{330}{2.5}=132 Hz

Learn more about wavelength and frequency:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

7 0
3 years ago
A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien
n200080 [17]

Answer:

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

\phi=NBA

Put the value into the formula

\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2

\phi=7.85\times10^{-7}\ Tm^2

We need to calculate the induced emf

Using formula of induced emf

\epsilon=\dfrac{d\phi}{dt}

Put the value into the formula

\epsilon=\dfrac{7.85\times10^{-7}}{dt}

Put the value of emf from ohm's law

\epsilon =IR

IR=\dfrac{7.85\times10^{-7}}{dt}

Idt=\dfrac{7.85\times10^{-7}}{R}

Idt=\dfrac{7.85\times10^{-7}}{0.50}

Idt=0.00000157=1.57\times10^{-6}\ C

We know that,

Idt=dq

dq=1.57\times10^{-6}\ C

We need to calculate the voltage across the capacitor

Using formula of charge

dq=C dV

dV=\dfrac{dq}{C}

Put the value into the formula

dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}

dV=1.57\ V

Hence, The voltage across the capacitor is 1.57 V.

5 0
3 years ago
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