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sweet-ann [11.9K]
2 years ago
12

A metal block has a density of 5000 kg per cubic meter and a mass of 15,000 kg. What is its volume?

Physics
1 answer:
Naily [24]2 years ago
4 0

Taking into account the definition of density, the volume of the metal block is 3 m³.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Volume of the metal block</h3>

In this case, you know that:

  • Density= 5000 \frac{kg}{m^{3} }
  • Mass= 15000 kg
  • Volume= ?

Replacing in the definition of density:

5000 \frac{kg}{m^{3} } =\frac{15000 kg}{volume}

Solving:

volume×5000 \frac{kg}{m^{3} }= 15000 kg

volume= \frac{15000 kg}{5000 \frac{kg}{m^{3} }}

<u><em>volume= 3 m³</em></u>

In summary, the volume of the metal block is 3 m³.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ12

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The oven draws 1100 W of power, and you have determined that it heats with an efficiency of 51%. Using this information, determi
LiRa [457]

Answer:

134.75935 seconds

Explanation:

m = Amount of water = 240 mL

c = Specific heat of water = 4.2 J/mL °C

\Delta T =  Change in temperature = 100-25=75

t = Time taken

P = Power = 1100 W

E = Pt

Efficiency = 51 %

So, Energy = 0.51Pt

As energy is conserved

Q = 0

\\\Rightarrow -mc\Delta T+E=0\\\Rightarrow -mc\Delta T+Pt=0\\\Rightarrow -240\times 4.2(100-25)+0.51\times 1100t=0\\\Rightarrow t=\frac{240\times 4.2(100-25)}{0.51\times 1100}\\\Rightarrow t=134.75935\ s

The it takes to raise the temperature is 134.75935 seconds

6 0
4 years ago
A motivated mule can accelerate an empty cart of mass m - 180 kg from rest to 5.0 m/s in 10 s.
kolezko [41]

When the mass of the cart changes, the time to travel at 4.6 m/s is 28.11 s.

<h3>Acceleration of the mule</h3>

The acceleration of mule is calculated as follows;

a = v/t

a = 5/10

a = 0.5 m/s²

<h3>For constant applied force</h3>

F1 = F2

m₁v₁/t₁ = m₂v₂/t₂

(180 x 5) / 10 = (550 x 4.6)/t

90 = 2530/t

t = 2530/90

t = 28.11 s

Thus, when the mass of the cart changes, the time to travel at 4.6 m/s is 28.11 s.

Learn more about acceleration here: brainly.com/question/14344386

5 0
2 years ago
The electric potential at a certain distance from a point charge can be represented by V. What is the value of the electric pote
Maksim231197 [3]

Answer:

<em>b. At twice the distance, the electric potential is V/2</em>

Explanation:

Electric potential

Is the amount of work needed to move a unit charge from a reference point (usually a point at infinity) without producing acceleration.

The electric potential due to a point charge q at a distance r is given by

\displaystyle V=K\frac{q}{r}

Where K is the Coulomb's constant. If we know the electric potential at a certain distance is V, if the distance is changed to 2r, then the new potential is

\displaystyle V'=K\frac{q}{2r}=\frac{1}{2}K\frac{q}{r}=\frac{1}{2}V

It means that the electric potential is half the previous value. Correct option: b.

8 0
3 years ago
A ball is thrown straight up into the air with an initial velocity of 50 ft/sec. The height h(t) of the ball after t seconds is
Scrat [10]

Answer:

The average velocity for the time period beginning when t=1 and lasting 0.1 seconds = 16.40 ft/s.

Explanation:

Given that the height of the ball at time t is

\rm h(t) = (50 t-16t^2)\ ft.

The average velocity of an object is defined as the total displacement covered by the particle divided by the total time taken in covering that displacement.

If \rm h_1,\ h_2 are the heights of the ball at time \rm t_1 and \rm t_2, then the total displacement covered by the ball from time \rm t_2 to \rm t_1 is \rm h_2-h_1.

Thus, the average velocity of the ball for the time interval \rm t_2-t_1  is given by

\rm v_{av}=\dfrac{h_2-h_1}{t_2-t_1}.

For the time interval, beginning when t = 1 second and lasting 0.1 seconds,

\rm t_1=1\ sec.\\t_2 = 1\sec + 0.1\ sec = 1.1\ sec.\\\\h_1=50\times 1-16\times 1^2=34\ ft.\\h_2=50\times 1.1-16\times 1.1^2=35.64\\\\Therefore,\\\\v_{av} = \dfrac{35.64-34}{1.1-1}=16.40\ ft/s.

7 0
4 years ago
Please HELP me label these symbols!!!!
Xelga [282]

Answer:

A is a battery

B is a light

C is a resistor

D is a closed switch

thank you for this question, I love circuit diagrams

Explanation:

4 0
3 years ago
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