1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sweet-ann [11.9K]
2 years ago
12

A metal block has a density of 5000 kg per cubic meter and a mass of 15,000 kg. What is its volume?

Physics
1 answer:
Naily [24]2 years ago
4 0

Taking into account the definition of density, the volume of the metal block is 3 m³.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Volume of the metal block</h3>

In this case, you know that:

  • Density= 5000 \frac{kg}{m^{3} }
  • Mass= 15000 kg
  • Volume= ?

Replacing in the definition of density:

5000 \frac{kg}{m^{3} } =\frac{15000 kg}{volume}

Solving:

volume×5000 \frac{kg}{m^{3} }= 15000 kg

volume= \frac{15000 kg}{5000 \frac{kg}{m^{3} }}

<u><em>volume= 3 m³</em></u>

In summary, the volume of the metal block is 3 m³.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ12

You might be interested in
Spring constant here for 22 cm spring is 50 N per metre 840 if you stretch the spring and when is measured again is 32 cm long w
seraphim [82]
K= fx => f = k/x => 50N/100cm / 10 cm = 5/10= 0.5 N
3 0
3 years ago
A tow truck is pulling a car out of a ditch by means of a steel cable (y = 2.0 x 1011 n/m2) that is 9.55 m long and has a radius
Anna11 [10]
If you know the real modulus of the cable (Y), the length, and the area (based on the radius), you can compute the spring constant, k = AE/L. Then, if you know the force used, you can compute the displacement, using F = kd, or d = F / k = FL/(AE). Our answer should work out to units of length. So, 
d = 803 N * 9.06 m / [pi*(0.574 cm)^2 * 2.0 x 10^11 N/m^2] 
d = 3.5 x 10^-8 Nm^3 / (cm^2 * N) 
d = 3.5 x 10^-8 m^3 / cm^2 * (100 cm / 1 m)^2 
d = 3.5 x 10^-4 m
4 0
3 years ago
Which wave, the top or bottom, has the larger frequency. explain why.
choli [55]
The b<span>ottom one because it has longer wavelengths and because the bottom ones has 3 wavelengths</span>
3 0
3 years ago
Please Help!.....................
Setler79 [48]
The awnser is tranverse wave
hope that helps

4 0
3 years ago
A girl (mass M) standing on the edge of a frictionless merry-go-round (radius R, rotational inertia I) that is not moving. She t
vladimir1956 [14]

a) \omega=\frac{-mvR}{I+MR^2}

b) v=\frac{-mvR^2}{I+MR^2}

Explanation:

a)

Since there are no external torques acting on the system, the total angular momentum must remain constant.

At the beginning, the merry-go-round and the girl are at rest, so the initial angular momentum is zero:

L_1=0

Later, after the girl throws the rock, the angular momentum will be:

L_2=(I_M+I_g)\omega +L_r

where:

I is the moment of inertia of the merry-go-round

I_g=MR^2 is the moment of inertia of the girl, where

M is the mass of the girl

R is the distance of the girl from the axis of rotation

\omega is the angular speed of the merry-go-round and the girl

L_r=mvR is the angular momentum of the rock, where

m is the mass of the rock

v is its velocity

Since the total angular momentum is conserved,

L_1=L_2

So we find:

0=(I+I_g)\omega +mvR\\\omega=\frac{-mvR}{I+MR^2}

And the negative sign indicates that the disk rotates in the direction opposite to the motion of the rock.

b)

The linear speed of a body in rotational motion is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the body from the axis of rotation

In this problem, for the girl, we have:

\omega=\frac{-mvR}{I+MR^2} is the angular speed

r=R is the distance of the girl from the axis of rotation

Therefore, her linear speed is:

v=\omega R=\frac{-mvR^2}{I+MR^2}

5 0
3 years ago
Other questions:
  • Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 165 cmcm , but its circumference is decrea
    11·1 answer
  • What causes the pressure that allows diamonds to form in the mantle
    8·2 answers
  • An image formed by a concave lens is <br> virtual/real
    15·1 answer
  • The driver of a car sets the cruise control and ties the steering wheel so that the car travels at a uniform speed of in a circl
    13·2 answers
  • Is it true that at freezing point particle are vibrating so fast they break free?
    14·2 answers
  • Fossil fuels currently account for the majority of the world’s energy use because they are A. renewable energy resources. B. dis
    15·1 answer
  • If a rock is thrown vertically upward from the surface of Mars with velocity 15 mys, its height after t seconds is h − 15t 2 1.8
    12·1 answer
  • A developmental psychologist would be interested in studying __________. A. different philosophies about life after death B. psy
    10·2 answers
  • An object of mass m is lowered at constant velocity at the end of a string of negligible mass. As it is lowered a vertical dista
    13·1 answer
  • Question 20
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!