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weeeeeb [17]
3 years ago
5

Do air bags increase pressure on the body during an accident

Physics
1 answer:
victus00 [196]3 years ago
7 0
Yes because once the accident has happen the air bag will then push out
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Why is it sometimes difficult for scientists to identify a a fold or fault?
Sauron [17]

Folds and faults are difficult to identify because they occur in the interior of rocks and also due to the dense nature of the materials.

<h3>What are faults and folds?</h3>

Faults are lines of weakness are present in materials dues to uneven positioning of the particles of the material.

Folds occurs when infolds occur in materials.

Faults and folds usually occur in rocks.

Folds and faults are difficult to identify because they occur internally and also due to the dense nature of the materials.

Learn more about faults and folds at: brainly.com/question/14240712

4 0
2 years ago
6. One minute after takeoff, a rocket carrying the space shuttle into outer space reaches a speed of 447 m/s.
Sidana [21]

Answer:

acceleration of the rocket is given as

a = 7.45 m/s^2

Explanation:

As we know that rocket starts from rest and then reach to final speed of 447 m/s after t = 1 min

so we have

v_i = 0

v_f = 447 m/s

t = 1 min = 60 s

so we have

a = \frac{v_f - v_i}{t}

a = \frac{447 - 0}{60}

a = 7.45 m/s^2

7 0
3 years ago
Why can Muhammad exert a greater punching force with his bare fist than he can while wearing a
weqwewe [10]

Answer:

the glove could be heavy so slowing down his power

Explanation:

JUST GUESSED

5 0
3 years ago
The solids settled at the bottom is called a) sludge b) sewage c) waste d) litter
Anna71 [15]

Answer:

the solid particles that settle down at the bottom of the container are known as sediment.

Explanation:

5 0
3 years ago
Four cylindrical wires of different sizes are made of the same material. Which of the following combinations of length and cross
anzhelika [568]

Answer:

Explanation:

For resistance of a wire , the formula is as follows .

R = ρ L/S

where ρ is specific resistance , L is length and S is cross sectional area of wire .

for first wire resistance

R₁ =  ρ 3L/3a = ρ L/a

for second wire , resistance

R₂ = ρ 3L/6a

= .5 ρ L/a

For 3 rd wire resistance

R₃ = ρ 6L/3a

= 2ρ L/a

For fourth wire , resistance

R₄ = ρ 6L/6a

=  ρ L/a

So the smallest resistance is of second wire .

Its resistance is .5 ρ L/a

7 0
3 years ago
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