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Rainbow [258]
3 years ago
10

When ethane (c2h6) reacts with chlorine (cl2) the main product is c2h5cl; but other products containing cl (chlorine), such as c

2h4cl2, are also obtained in small quantities. the formation of these other products reduces the yield of c2h5cl. in a certain experiment 145 g of c2h6 reacts with 215 g of cl2. (a) assuming that c2h6 and cl2 react only to form c2h5cl and hcl, calculate the theoretical yield of c2h5cl?
Physics
1 answer:
Deffense [45]3 years ago
5 0
The balanced chemical reaction is written as:

C₂H₆ + Cl₂ → C₂H₅Cl + HCl

Mol of C₂H₆ available: 145 g/ 30 g/mol = 4.833 mol
Mol of Cl₂ available: 215 g/ 70.9 g/mol = 3.032 mol

So, the limiting reactant is Cl₂. We base our theoretical yield from here.

3.032 mol Cl₂ (1 mol C₂H₅Cl/ 1 mol Cl₂)(64.45 g/mol C₂H₅Cl) = <em>195.41 g C₂H₅Cl</em>


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Calculate the total energy of 2.0 kg object moving horizontally at 10 m/s 50 meters above the surface
mina [271]
We have:

Total Energy: KE + GPE
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GPE (Gravitational Potential Energy) = m*g*h

Data:
m (mass) = 2.0 Kg
v (speed) = 10 m/s
h (height) = 50 m
Use: g (gravity) = 10 m/s²

Formula:

Total Energy: KE + GPE
TE =  \frac{1}{2} m*v^2 + m*g*h

Solving:
TE = \frac{1}{2} m*v^2 + m*g*h
TE = \frac{1}{2} *2.0*10^2 + 2.0*10*50
TE =  \frac{2.0*100}{2} + 1000
TE =  \frac{200}{2} + 1000
TE = 100 + 1000
\boxed{\boxed{TE = 1100\:Joule}}\end{array}}\qquad\quad\checkmark


5 0
3 years ago
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Does everything in a black hole contain a singularity?
Lapatulllka [165]
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8 0
2 years ago
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A rugby player runs with the ball directly toward his opponent's goal, along the positive direction of an x axis. He can legally
Over [174]

Answer:

minimum angle is 128.69°

Explanation:

given data

player velocity with respect ground v1 = 3.5 m/s

ball velocity with respect himself v2 = 5.6 m/s

to find out

smallest angle

solution

we know ball velocity with respect field will be

ball velocity = v1  +v2

ball velocity = 3.5 + 5.6 = 9.1m/s

we consider angle that player hit ball is θ

then by as per figure triangle

cosθ = \frac{v1}{v2}

cosθ = \frac{3.5}{5.6}

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3 years ago
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Answer:

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8 0
2 years ago
A particle with positive charge q = 9.61 10-19 C moves with a velocity v = (5î + 4ĵ − k) m/s through a region where both a unifo
user100 [1]

Answer:

\vec{F}=(1.537*10^{-17}\hat{i}-9.61*10^{-19}\hat{j}-2.883*10^{-18}\hat{k})N

Explanation:

The total force on the particle is given by

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Then, by replacing we have:

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where the cross product can be made with the determinant method.

Hope this helps!!

3 0
3 years ago
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