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marshall27 [118]
3 years ago
8

PLEASE HELP 15 POINTS AND BRAINIEST!!! Reporting fake answers

Physics
1 answer:
Leviafan [203]3 years ago
6 0
The period, speed and acceleration of a satellite are only dependent upon the radius of orbit and the mass of the central body that the satellite is orbiting. I hope this helps. Sorry if i am wrong.
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Using .125 mass kgwhat is the velocity​
agasfer [191]

Answer:

The answer is 5 meters per second.

6 0
3 years ago
Earth's oceans have an average depth of 3800 m, a total area of 3.63 × 108 km2, and an average concentration of dissolved gold o
ratelena [41]
To determine the mass of gold dissolved in oceans, we must first know the volume of the ocean in liters. To determine its volume, we multiply the area and the depth taking note of the consistency of units. The volume would be 1.38 x 10^18 cubic meters or 1.38x10^21 liters. Then,multiplying this to the concentration, the answer would be 8 x 10^12 grams or 8 billion kg.


3 0
4 years ago
When a car turns a corner on a level road, which force provides the necessary centripetal acceleration?
Vinil7 [7]

Answer:

The frictional force between the tire made with the road

Explanation:

This car on level ground is moving away and turning to the left. The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. A minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway.

5 0
3 years ago
Parallel conducting tracks, separated by 2.20 cm, run north and south. There is a uniform magnetic field of 1.20 T pointing upwa
mars1129 [50]

Answer:

The magnitude of the magnetic force on the rod is 0.037 N.

Explanation:

The magnetic force is given by:

F = qvBsin(\theta)

Since the charge (q) is:

q = I*t

Where<em> I</em> is the current = 1.40 A, and <em>t</em> the time  

And the speed (v):

v = \frac{L}{t}

Where <em>L </em>is the tracks separation = 2.20 cm = 0.022 m

Hence, the magnetic force is:

F = ILBsin(\theta)

Where <em>B </em>is the magnetic field = 1.20 T and <em>θ</em> is the angle between the tracks and the magnetic field = 90°

F = ILBsin(\theta) = 1.40*0.022*1.20*sin(90) = 0.037 N

Therefore, the magnitude of the magnetic force on the rod is 0.037 N.

I hope it helps you!

5 0
3 years ago
give three examples from the device on the apply page where potential energy was converted to kinetic energy
Elodia [21]

a water turbine drops water onto a blade which gains ke at water's gpe expense

4 0
3 years ago
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