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marshall27 [118]
3 years ago
8

PLEASE HELP 15 POINTS AND BRAINIEST!!! Reporting fake answers

Physics
1 answer:
Leviafan [203]3 years ago
6 0
The period, speed and acceleration of a satellite are only dependent upon the radius of orbit and the mass of the central body that the satellite is orbiting. I hope this helps. Sorry if i am wrong.
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The largest salami in the world, made in Norway, was more than 20 m long. If a hungry mouse ran around the salami’s circumferenc
Musya8 [376]

Answer: 0.09 m

Explanation:

Centripetal acceleration in terms of tangential speed is:

a_c=\frac{v^2_t}{r}

where r is the radius.

It is given that,

centripetal acceleration of the mouse, a_c=0.29 m/s^2

tangential speed , v_t=0.17m/s

Radius of salami is:

r =\frac{(0.17m/s)^2}{0.29 m/s^2}=0.09m

Thus, the radius of the salami is 0.09 m.

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3 years ago
Which of the following represents an image that is located in front of a lens?
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-di represents an image in front of a lens
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3 years ago
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Answer fast !!!!!!! pleaseee
wariber [46]

Answer: Magnetic Fields

Explanation:

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A laser emits two wavelengths (λ1 = 420 nm; λ2 = 630 nm). When these two wavelengths strike a grating with 450 lines/mm, they pr
Westkost [7]

A) Order of the first laser: 3, order of the second laser: 2

B) The overlap occurs at an angle of 34.9^{\circ}

Explanation:

A)

The formula that gives the position of the maxima (bright fringes) for a diffraction grating is

d sin \theta = m \lambda

where

d is spacing between the lines in the grating

\theta is the angle of the maximum

m is the order of diffraction

\lambda is the wavelength of the light

For laser 1,

d sin \theta = m_1 \lambda_1

For laser 2,

d sin \theta = m_2 \lambda_2

where

\lambda_1 = 420 nm\\\lambda_2 = 630 nm

Since the position of the maxima in the two cases overlaps, then the term d sin \theta on the left is the same for the two cases, therefore we can write:

m_1 \lambda_1 = m_2 \lambda_2\\\frac{m_1}{m_2}=\frac{\lambda_2}{\lambda_1}=\frac{630}{420}=\frac{3}{2}

Therefore:

m_1 = 3

m_2 = 2

B)

In order to find the angle at which the overlap occurs, we use the 1st laser situation:

d sin \theta = m_1 \lambda_1

where:

N = 450 lines/mm = 450,000 lines/m is the number of lines per unit length, so the spacing between the lines is

d=\frac{1}{N}=\frac{1}{450,000}=2.2\cdot 10^{-6} m

m_1 = 3 is the order of the maximum

\lambda_1 = 420 nm = 420\cdot 10^{-9} m is the wavelength of the laser light

Solving for \theta, we find the angle of the maximum:

sin \theta = \frac{m_1 \lambda_1}{d}=\frac{(3)(420\cdot 10^{-9})}{2.2\cdot 10^{-6}}=0.572

So the angle is

\theta=sin^{-1}(0.572)=34.9^{\circ}

Learn more about diffraction:

brainly.com/question/3183125

#LearnwithBrainly

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4 years ago
How do heat insulators work
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The heat is transferred to one material to another, however insulators minimize that transfer, keeping it in the area, warming it. 
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