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Stella [2.4K]
4 years ago
7

By using_______you can determine your exact position and altitude on earth?

Physics
1 answer:
kupik [55]4 years ago
4 0
By using a ''GPS'' you can determine your exact position and altitude on earth.
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Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay
Westkost [7]

Answer:

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model, m_1=0.205\ kg

Speed of the model, u_1=0.72\ m/s

Mass of another model, m_2=0.32\ kg

Initial speed of another model, u_2=0

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

6 0
3 years ago
What is the average velocity of a bowling ball that moves down the lane 8 meters in 4 seconds?​
Tema [17]

Answer: 2m/s

Explanation:

V avg = Displacement / time

Displacement is 8

Time is 4

V avg = 2

8 0
3 years ago
A bowling ball with a mass of 8 kg is moving at a speed of 5m/s. What is its kinetic energy
dolphi86 [110]

Answer:The formula for kinetic energy is

(1/2) M V^2.

With M in kg and V in m/s, the answer will be in Joules.

K.E = 40joule

Explanation:

4 0
3 years ago
A runner hopes to complete the 10,000m run in less than 30,0min, after running at constant speed for exactly 27.0 min , there ar
tankabanditka [31]
Well I figured out at his current pace, he would finish the 1100 remaining meters in 200 seconds. However, he needs to complete it in 180 seconds. I'm not sure how to find out how long he has to accelerate at 0.20 m/s/s to complete it in 180 seconds.

3 0
3 years ago
A piece of string 2 meters and has a mass of 5g. On one end of the string hangs a 200 g mass. Find the tension of the string and
viktelen [127]

Explanation:

It is given that,

Length of the string, l = 2 m

Mass of the string, m=5\ g=5\times 10^{-3}\ kg

Hanged mass in the string, m'=200\ g=0.2\ kg

1. The tension in the string is given by :

T=m'g

T=0.2\times 9.8

T = 1.96 N

2. Velocity of the transverse wave in the string is given by :

v=\sqrt{\dfrac{T}{M}}

m = M/l

v=\sqrt{\dfrac{Tl}{m}}

v=\sqrt{\dfrac{1.96\times 2}{5\times 10^{-3}}}

v = 28 m/s

Hence, this is the required solution.

4 0
3 years ago
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