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konstantin123 [22]
2 years ago
8

What does the signal word then accomplish in these sentences

Physics
2 answers:
zlopas [31]2 years ago
6 0
What are the sentences
zalisa [80]2 years ago
3 0
Picture? I can help!
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If the position of a particle on the x-axis at time t is −5t2, then the average velocity of the particle for 0 ≤ t ≤ 3 is
Drupady [299]

Answer:

v = 15 m / s

Explanation:

In this exercise we are given the position function

          x = 5 t²

and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval

          v= \frac{v_{f} - v_{o} }{t_{f} - t_{o} }

let's look for the displacements

        t = 0     x₀ = 0 m

        t = 3     x_{f} = 5 3 2

                     x_{f} = 45 m

 

we substitute

           v = \frac{45 -0}{3 - 0}

           v = 15 m / s

3 0
3 years ago
A person began running due east and covered 15 km in 2.0 hr. What is the average velocity of the person?
g100num [7]
Velocity = distance / time

v = (15*1000)m / (2*60*60)s

v=2.08 m / s
6 0
3 years ago
Read 2 more answers
What is impulse measured in
MrMuchimi
Impulse = Force * time
5 0
3 years ago
A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is r
aivan3 [116]

Answer:

Explanation:

Given that,

Initial angular velocity is 0

ωo=0rad/s

It has angular velocity of 11rev/sec

ωi=11rev/sec

1rev=2πrad

Then, wi=11rev/sec ×2πrad

wi=22πrad/sec

And after 30 revolution

θ=30revolution

θ=30×2πrad

θ=60πrad

Final angular velocity is

ωf=18rev/sec

ωf=18×2πrad/sec

ωf=36πrad/sec

a. Angular acceleration(α)

Then, angular acceleration is given as

wf²=wi²+2αθ

(36π)²=(22π)²+2α×60π

(36π)²-(22π)²=120πα

Then, 120πα = 8014.119

α=8014.119/120π

α=21.26 rad/s²

Let. convert to revolution /sec²

α=21.26/2π

α=3.38rev/sec

b. Time Taken to complete 30revolution

θ=60πrad

∆θ= ½(wf+wi)•t

60π=½(36π+22π)t

60π×2=58πt

Then, t=120π/58π

t=2.07seconds

c. Time to reach 11rev/sec

wf=wo+αt

22π=0+21.26t

22π=21.26t

Then, t=22π/21.26

t=3.251seconds

d. Number of revolution to get to 11rev/s

∆θ= ½(wf+wo)•t

∆θ= ½(0+11)•3.251

∆θ= ½(11)•3.251

∆θ= 17.88rev.

5 0
3 years ago
Read 2 more answers
To construct a solenoid, you wrap insulated wire uniformly around a plastic tube 7.1 cm in diameter and 57 cm in length. You wou
ASHA 777 [7]

Answer:

We need about 8769 meters of wire to produce a 2.6 kilogauss magnetic field.

Explanation:

Recall the formula for the magnetic field produced by a solenoid of length L. N turns, and running a current I:

B=\mu_0\,\frac{N}{L} \,I

So, in our case, where B = 2.6 KG = 0.26 Tesla; I is 3 amperes, and L = 0.57 m, we can find what is the number of turns needed;

B=\mu_0\,\frac{N}{L} \,I\\0.26=4\,\pi\,10^{-7}\frac{N}{0.57} \,3\\N=\frac{0.26*0.57\,10^7}{12\,\pi} \\N=39311.27

Therefore we need about 39312 turns of wire. Considering that each turn must have a length of \pi\,D, where D is the diameter of the plastic cylindrical tube, then the total length of the wire must be:

Length=39312\,(\pi\,D)=39312\,(\pi\,0.071)\approx 8768.66\,\,m

We can round it to about 8769 meters.

5 0
3 years ago
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