Question

For the same mixture, under the same conditions described in problem 7, calculate keq for 2nh3 (g) n2 (g) + 3h2(g). how is the keq for a forward reaction related to the keq for a reverse reaction

Answer 1

Answer: The relation between the forward and reverse reaction is $K_f=\frac{1}{K_r}$

Explanation:

For the given chemical equation:

$2NH_3(g)\rightleftharpoons N_2 (g)+3H_2(g)$

The expression of equilibrium constant for above equation follows:

$K_f=\frac{[N_2][H_2]^3}{[NH_3]^2}$         .......(1)

The reverse equation follows:

$N_2 (g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

The expression of equilibrium constant for above equation follows:

$K_r=\frac{[NH_3]^2}{[N_2][H_2]^3}$       .......(2)

Relation expression 1 and expression 2, we get:

$K_f=\frac{1}{K_r}$

Hence, the relation between the forward and reverse reaction is $K_f=\frac{1}{K_r}$