Answer:
B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.
Explanation:
Here,power has been calculated using current I and total EMF \ε . So,P=EMF*current= ε I will represent total power dissipated in resistor and ammeter.
Now, this total power P has been dissipated in both resistor and ammeter. So, power dissipated in resistor must be less than P as some power is also dissipated in ammeter because it has non-zero resistance.
So, the answer is B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.
Note that option A,C and E are ruled out as they state power dissipated by resistor is greater than or equal to P which is false.
Also,option D is ruled out as ammeter is connected in series.
Answer:
It is because they are physical quantities
Explanation:
I think so..
Ultraviolet light with a wavelength shorter than visible light and a higher radiant energy than visible light.
The shorter the wavelength, the higher the frequency and energy.
Answer:
You should conclude that the calibration of the thermometer is inaccurate
Explanation:
What is calibration?
calibration is the comparison of measurement values delivered by a device under test with those of a calibration standard of known accuracy.
What is a thermometer?
A thermometer is a measuring instrument used for checking temperature.
Answer:
0.19 m (19 cm)
Explanation:
The maximum speed in a simple harmonic motion is given by
(1)
where
A is the amplitude
is the angular frequency, which is given by
(2)
where T is the period.
By combining (1) and (2), we find
Here we know that
v = 60.0 cm/s = 0.6 m/s is the maximum speed
T = 2.00 s is the period
Substituting into the formula, we find the amplitude:
