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Nonamiya [84]
3 years ago
13

An executive invests 29,000, some at 8% and the rest at 7% annual interest. If he receives an annual return of $2,230, how much

is invested at each rate?
Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

Amount invested in A (8%) = $20,000

Amount invested in B (7%) = $9,000

Step-by-step explanation:

Given:

Total amount invested = $29,000

Interest rate A = 8% = 0.08

Interest rate B = 7% = 0.07

Annual return = $2,230

Find:

Amount invested in each

Computation:

Assume;

Amount invested in A = x

Amount invested in B = 29,000 - x

So,

Interest receive from A = x × 0.08

Interest receive from A = 0.08 x

Interest receive from B = (29000 - x) × 0.07

Interest receive from B = 2,030 - 0.07 x

Annual return = Interest receive from A + Interest receive from B

2,230 = 0.08 x + 2,030 - 0.07 x

x = 20,000

Amount invested in A = $20,000

Amount invested in B = 29,000 - $20,000

Amount invested in B = $9,000

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       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

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a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

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