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german
4 years ago
11

What is it called when air pressure at sea level is 101.3

Physics
1 answer:
creativ13 [48]4 years ago
3 0
It is called Atmospheric Pressure
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The lowest-pitch tone to resonate in a pipe of length L that is closed at one end and open at the other end is 200 Hz. Which one
ozzi

Answer:

e. 400 Hz

Explanation:

In closed organ pipe,  only odd harmonics of fundamental note is possible .

The fundamental frequency is 200 Hz . Then other overtones will be having following frequencies .

200 x 3 , 200 x 5 , 200 x 7 , 200 x 9 etc

600 Hz , 1000 Hz , 1400 Hz  , 1800 Hz .

Frequency not possible is 400 Hz .

7 0
4 years ago
efrigerant-134a is expanded isentropically from 600 kPa and 70°C at the inlet of a steady-flow turbine to 100 kPa at the outlet.
PolarNik [594]

Answer:

Inlet : v_i=0.0646\frac{m}{s}

Outlet:  v_o=0.171\frac{m}{s}

Explanation:

1) Notation and important concepts

Flow of mass represent "the mass of a substance which passes per unit of time".

Flow rate represent "a measure of the volume of liquid that moves in a certain amount of time"

Specific volume is "the ratio of the substance's volume to its mass. It is the reciprocal of density."

Isentropic process is a "thermodynamic process, in which the entropy of the fluid or gas remains constant".

We know that the flow of mass is given by the following expression

\dot{m}=\frac{\dot{V}}{\upsilon}, where \dot{V} represent the flow rate and \upsilon the specific volume at the pressure and temperature given.

A_i=0.5m^2 is the inlet area

P_i=600Kpa pressure at the inlet area

T_i=70C temperature at the inlet area

A_o=1m^2 is the outlet area

P_o=100Kpa pressure at the outlet area

T_o=C temperature at the outlet area

\dot{m}=0.75\frac{kg}{s} represent the flow of mass

If we look at the first figure attached Table A-13 we see that the specific volume for the inlet condition is

\upsilon_i =0.04304\frac{kg}{m^3} and the entropy is h_i=1.0645\frac{KJ}{KgK}=h_o

With the value of entropy and the outlet pressure of 100 Kpa we can find we specific volume at the outlet condition since w ehave the entropy h_o=1.0645\frac{KJ}{KgK}

Since on the table we don't have the exact value we need to interpolate between these two values (see the second figure attached)

h_1=1.0531\frac{KJ}{KgK} , \upsilon_1=0.22473\frac{kg}{m^3}

h_2=1.0829\frac{KJ}{KgK} , \upsilon_2=0.23349\frac{kg}{m^3}

Our interest value would be given using interpolation like this:

\upsilon=0.22473+\frac{(0.23349-0.22473)}{(1.0829-1.0531)}(1.0645-1.0531)=0.228\frac{kg}{m^3}

2) Solution to the problem

Now since we have all the info required to solve the problem we can find the velocities on this way.

We know from the definition of flow of mass that \dot{m}=\frac{\dot{V}}{\upsilon}, but since \dot{V}=Av we have this:

\dot{m}=\frac{Av}{\upsilon}

If we solve from the velocity v we have this:

v=\frac{\upsilon \dot{m}}{A}   (*)

And now we just need to replace the values into equation (*)

For the inlet case:

v_i=\frac{\upsilon_i \dot{m}}{A_i}=\frac{0.043069\frac{kg}{m^3}(0.75\frac{kg}{s})}{0.5m^2}=0.0646\frac{m}{s}

For the oulet case:

v_o=\frac{\upsilon_o \dot{m}}{A_o}=\frac{0.228\frac{kg}{m^3}(0.75\frac{kg}{s})}{1m^2}=0.171\frac{m}{s}

7 0
3 years ago
A projectile is launched at an angle of 60° from the horizontal and at a velocity of
gayaneshka [121]

Answer:

60*12.0= 720 = v/60 * 12.0 squared which is 1,728

Explanation:

Horizontal velocity component: Vx = V * cos(α)

5 0
3 years ago
Dont skip and pls help ASAP bc if you do i will give 10 pts + brainliest but pls hurry
Fed [463]

ANSWER

Mass: The resistance of an object to acceleration, size-dependent

Volume: The amount of space an object occupies

Boiling point: The temperature at which a liquid boils and turns to vapor.

Melting point: The temperature at which a solid melts and turns to liquid

Density: Size-independent

Solubility: The ability of a substance (solvent) to dissolve when placed in a liquid (solute)

Magnetism: Size-dependent

EXPLANATION:

Mass: the more mass something has, the harder it is to accelerate. This is somewhat intuitive, but is also demonstrated in newton's third law. It's size-dependent because for an object of a given density, the size (volume) will change the mass.

Volume: big objects take up more space. If you put an apple in bucket filled to the brim with water, a little water will splash out, because the apple is now occupying the space that the water used to, but if you put in a watermelon, a lot of water will splash out, because the watermelon is taking up even more space.

Boiling point: when a liquid gets too hot, it will change to gas (example: water to steam)

Melting point: when a liquid gets too cold, it will change to a solid (example: water to ice)

Density: how much mass there is in a given volume. A sphere made of lead will have more mass than a sphere made of wood, even if they are the same size. Size-independent because a big lead sphere has the same density as a small lead sphere, they just have different masses.

Solubility: some substances dissolve in certain solvents, other's don't.

Magnetism: size-dependent because a bigger magnet is stronger than a smaller one if they are identical in every other way. More space means more domains means a stronger magnet.

7 0
3 years ago
Read 2 more answers
In an experiment what are all the parts of an experiment that remain unchanged are called<br>​
stira [4]
The answer for this question is Control Variable because it doesn’t change throughout the experiment.
3 0
4 years ago
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