NEED HELP!!!!!

A proposed communication satellite would revolve around the earth in a circular orbit in the equatorial plane at a height of 358

aleksandr82 [10.1K]

Answer:

Period is 86811.5 seconds.

Explanation:

${ \boxed{ \bf{T {}^{2} = (\frac{4 {\pi}^{2} }{GM}) {r}^{3} }}}$

${ \tt{T {}^{2} = \frac{4 {(3.14)}^{2} }{(6.6 \times {10}^{ - 11} ) \times (5.98 \times {10}^{24} )} \times {((35880\times {10}^{3}) } + (6370 \times {10}^{3} )) {}^{3} }} \\ \\ { \tt{T {}^{2} = 7.54 \times {10}^{9} }} \\ { \tt{T = \sqrt{7.54 \times {10}^{9} } }} \\ { \tt{T = 86811.5 \: seconds}}$

6 0

3 years ago

•<br> What happens to similar charged<br> particles and differently charged<br> particles

mixas84 [53]

Answer:

Like charges repel

Different charges attract

Explanation:

When particles of similar charges are brought together, they repel each other and increase the distance of separation. Repulsion occurs because both two electrons have negative electrical charge forcing their lines of force to repel. However, when particles of opposite charges are brought nearer to each other, they attract each other and reduce the distance of separation.

8 0

3 years ago

A physicist makes a cup of instant coffee and notices that, as the coffee cools, its level drops 3.00 mm in the glass cup. Show

Lady bird [3.3K]

Answer:

change in height is 1.664 mm

Explanation:

Given data

drops = 3.00 mm

diameter = 5.00 cm = 0.05 mm

decrease = 350 cm^3

temperature = 95°C to 44.0°C

to find out

the decrease in millimeters in level

solution

we will calculate here change in volume so we can find how much level is decrease

change in volume = β v change in temp ...............1

here change in volume = area× height

so = $\pi$ /4 × d² h

so we can say change in volume = $\pi$ /4 × d² × change in height .......2

so from equation 1 and 2 we calculate change in height

( β(w) -β(g) )× v× change in temp = $\pi$ /4 × d² × change in height

change in height = 4 × ( β(w) -β(g) ) v× change in temp / $\pi$ /4 × d²

put all value here

change in height = 4 × ( 210 - 27 )(350 ) $10^{-6}$ × (95-44) / $\pi$ /4 × 0.05²

change in height is 1.664 mm

5 0

3 years ago

Ballon volume of 3200ml of xenon gas is at a gauge pressure of 122kPa and a temperature of 27c. What is the volume when the ball

N76 [4]

Given:

The initial volume of the gas, V₁=3200 ml=3.2×10⁻³ m³

The initial pressure of the gas, P₁=122 kPa

The initial temperature of the gas, T₁=27 °C=300 K

The final temperature, T₂=65 °C=338 K

The final pressure, P₂=112 kPa

To find:

The final volume of xenon gas.

Explanation:

From the combined gas law,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

Where V₂ is the volume after it is heated.

On rearranging the above equation,

$V_2=\frac{T_2P_1V_1}{T_1P_2}$

On substituting the known values,

$\begin{gathered} V_2=\frac{338\times112\times10^3\times3.2\times10^{-3}}{300\times112\times10^3} \\ =3.61\text{ m}^3 \end{gathered}$

Final answer:

The volume of the balloon when it is heated is 3.61 m³

4 0

1 year ago

Megan wants to see if mice the are fed food A or B grow faster rate. She measures the mass of the mice on day 1 then divides the

Setler79 [48]

yes megan does her control is the amount of food given and what food is given between 2 groups and when they are fed all of this concludes to it being a control group hope i helped and please give me brainliest

5 0

4 years ago