Answer:
9
Explanation:
You divide the joules by the coulombs to find the voltage of the battery so, 27/3= 9
Answer:
2.8 seconds
Explanation: Given that a simple pendulum that consists of a massless 2.00-meter length of rope attached to a 5.00-kg mass at one end. What is the period of oscillation for this simple pendulum
The parameters given are :
Length = 2 m
Mass = 5kg
Using the formula below
T = 2 pi × sqrt ( L / g )
Substitute all the parameters into the formula.
T = 2 × 3.143 × sqrt ( 2 / 9.8 )
T = 2 × 3.143 × 0.4517
T = 2.838 s
Therefore, the period of oscillation for this simple pendulum is 2.8 s approximately.
Answer:
<em>39428.93 N/m²</em>
Explanation:
Pressure: This can be defined as the force acting normally perpendicularly per unit area of surface. The S.I unit of pressure is N/m²
The pressure in a fluid is given as
P = ρgh............................. Equation 1
Where P = pressure, ρ = density, h = height, g = acceleration due to gravity.
Note: The North Atlantic is an ocean, and it contains water
Given: h = 2.5 mile
If 1 mile =
1 609.344 meters,
Then 2.5 miles = (1609.344×2.5 ) m = 4023.36 m.
Constant: g = 9.8 m/s², ρ = density of water = 1.0 g/m³
Substituting these values into equation 1
P = 1×4023.36×9.8
p = 39428.93 N/m²
<em>Thus the pressure at that depth = 39428.93 N/m²</em>
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Velocity=frequency(wavelength)
24m/s=f(2m)
24/2=f(2)/2
12Hz=f
