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balandron [24]
3 years ago
15

The average earth-sun distance is 1.50 × 10^11 m. How long does it take sunlight to reach the earth?

Physics
1 answer:
aalyn [17]3 years ago
5 0

Answer:

8.33 minutes

Explanation:

Distance between Earth and Sun = 1.5×10¹¹ m

Speed of light = 3×10⁸ m/s

Time = Distance / Speed

\text{Time taken}=\frac{1.5\times 10^{11}}{3\times 10^8}\\\Rightarrow \text{Time taken}=500\ seconds

500\ seconds=\frac{500}{60}=8.33\ minutes

∴ Time it takes for sunlight to reach the Earth is 8.33 minutes.

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Fig. 2.1 shows a train
Vitek1552 [10]

Answer:

\mathrm{(a)\:}32,000,000\:\mathrm{Ns},\\\mathrm{(b)\:}390,000\:\mathrm{N}

Explanation:

The impulse-momentum theorem states the impulse on an object is equal to the change in momentum of that object. Momentum is given by p=mv. Since mass is constant, the train's change in momentum is:

\Delta p=m\Delta v=750,000\cdot42=31,500,000=\fbox{$32,000,000\:\mathrm{Ns}$}(two significant figures).

Impulse is also given as \Delta p = F\Delta t, where F is the average force applied and \Delta t is change in time. Since t is given as 80\mathrm{s}, we have the following equation:

F\Delta t=\Delta p\\\\F=\frac{\Delta p}{\Delta t},\\\\F=\frac{31,500,000}{80},\\\\F=393,750=\fbox{$390,000\:\mathrm{N}$}(two significant figures).

7 0
3 years ago
On the way to school, Jed traveled 100m north, 300m east, 100 north, 100m east, and 100m north. A.) Find the total distance trav
Oduvanchick [21]

Answer:

Total distance = 700 m

Displacement = 500 m

Explanation:

Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is:  300 + 400 = 700 m.

But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:

displacement = \sqrt{300^2+400^2} =\sqrt{250000} =500\,m

5 0
3 years ago
You wish to buy a motor that will be used to lift a 10-kg bundle of shingles from the ground to the roof of a house. The shingle
gogolik [260]

Answer:

\tau=19.21\ N-m

Explanation:

It is given that,

Mass of bundle of shingles, m = 10 kg

Upward acceleration of the shingles, a=1.5\ m/s^2

The radius of the motor of the pulley, r = 0.17 m

Let T is the tension acting on the shingles when it is lifted up. It can be calculated as :

T-mg=ma

T=m(g+a)

T=10\times (9.8+1.5)

T = 113 N

Let \tau is the minimum torque that the motor must be able to provide. It is given by :

\tau=r\times T

\tau=0.17\times 113

\tau=19.21\ N-m

So, the minimum value of torque is 19.21 N-m. Hence, this is the required solution.

4 0
3 years ago
Vector sum of 15 m, East and 9 m, West is 24 m, East. True False
Firlakuza [10]

Answer:

False

Explanation:

Because when you go through east

( +x axis ) then you go to west ( -x axis )

You will subtract -9 from +15

it's become +6

( I talk about the displacement not distance) ( West = - East )

I hope that it's a clear ") .

7 0
3 years ago
Read 2 more answers
5.37 At steady state, a power cycle develops a power output of 10 kW while receiving energy by heat transfer at the rate of 10 k
Anika [276]

Answer: minimum theoretical value of T = 750k

Explanation:

Assuming the the cycle is reversible and is ideal then

Wnet/Qh = Nmin .... equa 1

Equation 1 can be rewritten as

(Th -TL)/ Th ...equation 2

Th= temp of hot reservoir

TL= temp of low reservoir= 300

Wnet = power generated=10kw

He = energy transfer=10kj per cycle

Qhe = power transfer = (100/60)*10Kj = 16.67kw

Sub into equat 1

Nmin = 10/16.67 = 0.6

Sub Nmin into equation 2

Th = -TL/(Nmin -1) = -300k/(0.6 - 1)

Th =750k

4 0
3 years ago
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