At what speed, in m/s, would a moving clock lose 1.3ns in 1.0 day according to experimenters on the ground?

Susie rides down and to the right on a slide for a total displacement of -3m at an angle of 45 degrees above the ground. What wa

Svetlanka [38]

Susie's vertical displacement is 2.1 m

Explanation:

In order to solve this problem, we have to resolve the displacement vector along the vertical direction.

The vertical component of a vector is given by:

$v_y = v sin \theta$

where

v is the magnitude of the vector

$\theta$ is the angle between the direction of the vector and the horizontal

Therefore, the vertical component of the displacement in this problem is given by

$d_y = d sin \theta$

where

d = 3 m is the magnitude of the displacement

$\theta=45^{\circ}$ is the angle between the displacement and the horizontal

Substituting, we find

$d_y = (3)(sin 45^{\circ})=2.1 m$

Learn more about vector components:

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6 0

4 years ago

Estimate and determine the order of magnitude of the circumference of the Earth in miles and the speed of a sailboat in miles pe

solmaris [256]

Answer:

= 1000 hours

Explanation:

Earth's circumference is 10⁴ mile

speed of a sailboat is 10¹ mile/hour

distance = speed × time

10⁴ = 10¹ × t

t = 10⁴ / 10¹

t = 10³

= 1000 hours

4 0

3 years ago

An object moving in circular motion has a mass of 15 kg and a centripetal acceleration of 10 m/s2. What is the centripetal force

sweet-ann [11.9K]

Answer:

1) A

2) C

3) B

4) A

5) Incomplete information(picture missing)

6) Incomplete information(picture missing)

7) Incomplete information(picture missing)

8) A

9) C

10) C

Explanation:

1) m = 15kg, a = $10ms^{-2}$ , F = ma = 15*10 = 150N

2) m = 3kg, v = $4ms^{-1}$ , r = 4m, F = $\frac{mv^{2} }{r}$

$\frac{3*4^{2} }{4}$ = 12N

3) a = $10ms^{-2}$ , r = 10m, v=?

F = $\frac{mv^{2} }{r}$ and F = ma

equating the two equations and cancelling a, we have:

$\frac{v^{2} }{r}$ = a

making v the subject of formula, we have:

v = $\sqrt{ar}$

= $\sqrt{100}$

= 10 $ms^{-1}$

4) r = 10m, v = $5ms^{-1}$ , a = ?

F = $\frac{mv^{2} }{r}$

F = ma

equating the above equations and making a subject of formula, we get:

a = $\frac{v^{2} }{r}$

a = 25/10 = 2.5 $ms^{-2}$

5) I can't find the picture associated with this question

6) I can't find the picture associated with this question

7) I can't find the picture associated with this question

8) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is tripled

F = $(3v)^{2}$

F = 9 $v^{2}$

We can see that the force will be 9X greater than it was.

9) F = $\frac{mv^{2} }{r}$

assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:

F = $v^{2}$

Now, if v is doubled

F = $(2v)^{2}$

F = 4 $v^{2}$

We can see that the force will be 4X greater than it was.

10) F = $\frac{mv^{2} }{r}$

assuming m and v is unity, that is the values are 1 respectively

F = 1/r

if r is doubled,

F = 1/2 * 1/r

We can see that the force is 1/2 as big as it was

7 0

3 years ago

A severe storm on January 10, 1992, caused a cargo ship near the Aleutian Islands to spill 29,000 rubber ducks and other bath to

Anna35 [415]

The distance that the rubber ducks traveled = 1600 miles.
The time taken to travel this distance = 10 months.

By definition, the approximate average speed of the ocean is
v = (1600 miles)/(10 months)

Note that
1 mile = 1609 m
10 months = (10 months)*(30 days/month) *(24 hours/day)
= 7200 hours (approx.)
= 7200*3600 = 2.592 x 10⁷ s

Therefore
$v = \frac{(1600 \, m)*(1609 \, \frac{m}{mi}) }{(10 \, months)*(2.592 \times 10^{7} \, \frac{s}{10 \, months}) } = 0.0993 \, \frac{m}{s}$

Also,
$v = \frac{1600 \, m}{7200 \, h} =0.222 \, \frac{mi}{h}$

Answer:
The average velocity is approximately 0.1 m/s, or 0.222 m/h.

6 0

3 years ago

What property of most stars can be determined by their color?

just olya [345]

I think it’s luminosity. I really hope it’s right and helped you.

4 0

4 years ago