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Rainbow [258]
3 years ago
6

The equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfe

rs 2 electrons? the equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfers 2 electrons? 0.23 v 0.47 v 0.16 v 0.86 v
Chemistry
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

0.23 V.

Explanation:

<em>∵ ΔG° = -RT lnK.</em>

∴ ΔG° = -RTlnK = -(8.314 J/mol)(298 K) ln(7.3 × 10⁷) = - 44.86 x 10³ J/mol.

<em>∵ ΔG° = - nFE°</em>

∴ E° = - ΔG°/nF = - (- 44.86 x 10³ J/mol)/(2 x 96500 s.A/mol) = 0.2324 V ≅ 0.23 V.

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Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi
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Explanation:

The given cell reaction is as follows.

       In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)

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At cathode; Reduction-half reaction : Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s) ....... (2)

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4 0
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Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /
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Answer:

[Pb^{2+}]=3.9 \times 10^{-2}M

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Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

Ip=[Pb^{2}][2Cl^-]^2=Ksp

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lets solubility=S

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Ksp=[Pb^{2+}]\times [Cl^-]^2

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S=\sqrt[3]{\frac{Ksp}{4} }

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