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2 years ago

Who summarized Greek medical knowledge in a textbook that would dominate medical teaching until the Scientific Revolution?

Chemistry

2 answers:

ss7ja [257]2 years ago

3 0

I recently wrote a paper on animal testing

Pretty sure it was Galen

Mashcka [7]2 years ago

3 0

Answer:

Explanation:

Aelius Galenus wrote the first anatomy textbook based on human dissection. His original works gained popularity for his remarkable job.

In Europe, during Middle Age, his textbooks were the main reference for medicine.

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A runner completes a 5-mile run.how many yards did she run

slega [8]

The runner ran a total of 8800 yards.

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3 years ago

6. A box measures 11.25 inches in length, 8.1 inches in width and 6.85 inches in height. What is the

denis23 [38]

Answer:

I'd say 624.2^3 inches.

Explanation:

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2 years ago

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2 years ago

Read 2 more answers

It is found that a gas undergoes a first-order decomposition reaction. If the rate constant for this reaction is 8.1 x 10-2 /min

kap26 [50]

Answer:

28.43 min

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given that:

The rate constant, k = $8.1\times 10^{-2}$ min⁻¹

Initial concentration $[A_0]$ = 0.1 M

Final concentration $[A_t]$ = $1.0\times 10^{-2}$ M

Time = ?

Applying in the above equation, we get that:-

$1.0\times 10^{-2}=0.1e^{-8.1\times 10^{-2}\times t}$

$0.1e^{-8.1\times \:10^{-2}t}=10^{-2}$

$e^{-8.1\times \:10^{-2}t}=\frac{1}{10}$

$\ln \left(e^{-8.1\times \:10^{-2}t}\right)=\ln \left(\frac{1}{10}\right)$

$t=28.43\ min$

3 0

3 years ago

An antacid tablet with an active ingredient of CaCO3 was dissolved in 50.0 mL of 0.300 M HCl. When this solution was titrated wi

yaroslaw [1]

Answer:

Explanation:

mole of HCl remaining after reaction with CaCO₃

= .3 M of NaOH of 32.47 mL

= .3 x .03247 moles

= .009741 moles

Initial HCl taken = .3 x .005 moles = .0015 moles

Moles of HCl reacted with CaCO₃

= .009741 - .0015 = .008241 moles

CaCO₃ + 2HCl = CaCl₂ + CO₂ + H₂O .

1 mole 2 moles

2 moles of HCl reacts with 1 mole of CaCO₃

.008241 moles of HCl reacts with .5 x .008241 moles of CaCO₃

CaCO₃ reacted with HCl = .5 x .008241 = .00412 moles

the mass (in grams) of calcium carbonate in the tablet

= .00412 x 100 = .412 grams . ( molar mass of calcium carbonate = 100 )

5 0

2 years ago