Answer:
pH = 12.15
Explanation:
To determine the pH of the HCl and KOH mixture, we need to know that the reaction is a neutralization type.
HCl + KOH → H₂O + KCl
We need to determine the moles of each compound
M = mmol / V (mL) → 30 mL . 0.10 M = 3 mmoles of HCl
M = mmol / V (mL) → 40 mL . 0.10 M = 4 mmoles of KOH
The base is in excess, so the HCl will completely react and we would produce the same mmoles of KCl
HCl + KOH → H₂O + KCl
3 m 4 m -
1 m 3 m
As the KCl is a neutral salt, it does not have any effect on the pH, so the pH will be affected, by the strong base.
1 mmol of KOH has 1 mmol of OH⁻, so the [OH⁻] will be 1 mmol / Tot volume
[OH⁻] 1 mmol / 70 mL = 0.014285 M
- log [OH⁻] = 1.85 → pH = 14 - pOH → 14 - 1.85 = 12.15
The nomenclature of binary covalent compounds follows these rules: The first element in the formula is given first, using the element's full name.
...
Binary molecular (covalent) compounds.
compound systematic name common name
NO nitrogen monoxide nitric oxide
NO2 nitrogen dioxide
N2O3 dinitrogen trioxide
N2O4 dinitrogen tetroxide
Answer:
The answer to your question is the letter A) 277°K
Explanation:
Data
Temperature 4°C
Formula
There are 3 main units to measure temperature Celsius, Fahrenheit and Kelvin.
To convert °C to °K just add 273°K to the temperature in °C.
°K = °C + 273
Substitution
°K = 4 + 273
Simplification and result
°K = 277°K
Answer: 36.07%
Explanation: Please see attachment for explanation
