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3 years ago

Which of the following aqueous solutions would have the greatest freezing-point depression?

Chemistry

1 answer:

lapo4ka [179]3 years ago

7 0

The greatest aqueous freezing point is (D) 0.10 KCI

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Use the information in the table to describe the temperature-vs.-time diagrams.

lara31 [8.8K]

Answer:

At 30 and 2,204

diagonal

liquid phase

2856

top horizontal line

flat

the change from a solid to a liquid

Explanation:

3 0

3 years ago

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

PLEASE HELP

Olin [163]

Answer:

40.097 g

Explanation:

No explanation needed

5 0

3 years ago

A 4 kg rock is rolling 10 m/s. Find its kinetic energy

Pavel [41]

KE = 1/2mv^2
KE = 1/2(4)*10 m/s^2
KE = 2 * 10
KE = 20 joules

Answer: 20 joules

8 0

3 years ago

WHAT MASS OF WATER WILL BE PRODUCED FROM 2.70 MOLES OF CA(OH)2 REACTING WITH HCI

Keith_Richards [23]

<u>Answer:</u> The mass of water produced in the reaction is 97.2 grams

<u>Explanation:</u>

We are given:

Moles of calcium hydroxide = 2.70 moles

The chemical equation for the reaction of calcium hydroxide and HCl follows:

$Ca(OH)_2+HCl\rightarrow CaCl_2+2H_2O$

By Stoichiometry of the reaction:

1 mole of calcium hydroxide produces 2 moles of water

So, 2.70 moles of calcium hydroxide will produce = $\frac{2}{1}\times 2.70=5.40mol$ of HCl

To calculate mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of water = 18 g/mol

Moles of water = 5.40 moles

Putting values in above equation, we get:

$5.40mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(5.40mol\times 18g/mol)=97.2g$

Hence, the mass of water produced in the reaction is 97.2 grams

3 0

4 years ago