Answer:
The correct option is: CO₂
Explanation:
Greenhouse effect refers to the natural phenomenon by which the Sun's radiation increases the temperature of the Earth's surface.
The incoming Sun's radiation is radiated by the greenhouse gases present in the Earth's atmosphere. A fraction of the radiated energy is then absorbed by the Earth's surface, thus resulting in increase in the temperature.
<u>Thus the green house effect depends upon the amount of green house gases present in the atmosphere.</u>
The green house gases are the r<u>adiatively active gases.</u> The main four green house gases are: water vapor (H₂O(g)), carbon dioxide (CO₂), methane (CH₄) and ozone (O₃).
<u>Human activities such as burning of fossil gases and deforestation increases the concentration of </u><u>CO₂ </u><u>significantly.</u><u> Thereby contributing to the greenhouse effect.</u>
Answer:
c
Explanation:
because heat is taken in in sublimation.
Answer:
a. NH3 is limiting reactant.
b. 44g of NO
c. 40g of H2O
Explanation:
Based on the reaction:
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)
4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.
To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:
<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>
25g NH3*(1mol/17.031g) = 1.47moles NH3
Moles O2 = 4 moles
For a complete reaction of 4 moles of O2 are required:
4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.
As there are just 1.47 moles, NH3 is limiting reactant
b. Moles NO:
1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO
Mass NO -Molar mass: 30.01g/mol-
1.47mol NO * (30.01g/mol) = 44g of NO
c. Moles H2O:
1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O
Mass H2O -Molar mass: 18.01g/mol-
2.205mol H2O * (18.01g/mol) = 40g of H2O
Empirical formula is the simplest ratio of components making up the compound. the molecular formula is the actual ratio of components making up the compound.
the empirical formula is CH₂. We can find the mass of CH₂ one empirical unit and have to then find the number of empirical units in the molecular formula.
Mass of one empirical unit - CH₂ - 12 g/mol x 1 + 1 g/mol x 2 = 12 = 14 g
Molar mass of the compound is - 252 .5 g/mol
number of empirical units = molar mass / mass of empirical unit
= 
= 18 units
Therefore molecular formula is - 18 times the empirical formula
molecular formula - CH₂ x 18 = C₁₈H₃₆
molecular formula is C₁₈H₃₆
