A) that something new had formed.
Answer : 6.41 moles of silicon are in the sample.
Solution : Given,
Moles of magnesium = 9.62 moles
The given chemical formula for talc is, 
From the given chemical formula we conclude that
The stoichiometry of magnesium and silicon is 3 : 2
3 moles of magnesium is equivalent to 2 moles of silicon
9.62 moles of magnesium will be equivalent to 
moles of silicon
Therefore, the number of silicon present in sample are 6.41 moles.
Answer:
9.34 cm³
Explanation:
From the question given, we obtained the following data:
Mass of magnesium = 16.24 g
Volume of magnesium =.?
To obtain the volume of the magnesium sample, we simply apply the formula for calculating the density of samples. This is illustrated below:
Mass of magnesium = 16.24 g
Density of magnesium 1.738 g/cm³
Volume of magnesium =.?
Density = mass /volume
1.738 = 16.24/volume
Cross multiply
1.738 × volume = 16.24
Divide both side by 1.738
Volume of magnesium = 16.24/1.738
Volume of magnesium = 9.34 cm³
Therefore, the density of the magnesium sample is 9.34 cm³.
1 is c 2 is b 3 is 1 d 4 is a
Answer:
A. 0.2395 w/w %
B. 2394ppm
Explanation:
A. To find concentrationin percent by mass of the solution we need to calculate mass of glycerol and mass of water. The formula is:
Mass glycerol / Total mass * 100
<em>Mass glycerol:</em>
The solution is 2.6x10⁻²moles / L. As there is 1L of solution there are 2.6x10⁻² moles of glycerol. In mass (Using molar mass glycerol: 92.09g/mol):
2.6x10⁻² moles of glycerol * (92.09g / mol) = 2.394g glycerol
<em>Mass of water:</em>
998.9mL and density = 0.9982g/mL:
998.9mL * (0.9982g/mL) = 997.1g of water.
That means percent by mass is:
% by mass: 2.394g / (997.1g + 2.394g) * 100 = 0.2395 w/w %
B. Parts per million are mg of glycerol per L of solution. As in 1L there are 2.394g. In mg:
2.394g * (1000mg / 1g) = 2394mg:
Parts per million: 2394mg / L = 2394ppm
