Answer:
The scientific name of the grasshopper is Caelifera.
Explanation:
hope this helps.
Crystal system
Hardness
Tenacity or Toughness
The given question is incomplete, here is a complete question.
At 400 K, this Reaction has 

What Is
at 400 K for the following reaction?

(A) 8.2 x 10⁻⁴
(B) 2.9 x 10⁻²
(C) 6.7 x 10⁻⁷
(D) 1.6 x 10⁻⁷
Answer : The correct option is, (C) 
Explanation :
The given chemical equation follows:

The equilibrium constant for the above equation,
.
We need to calculate the equilibrium constant for the following equation of above chemical equation, which is:
, 
The equilibrium constant for the doubled reaction will be the square of the initial reaction.
Or, we can say that
If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.
The value of equilibrium constant for the following reaction is:



Hence, the value of equilibrium constant for the following reaction is, 
The correct answer is C. There is no oxygen in space, so there can be no combustion.
Explanation:
Fire and flames are the result of a chemical process known as combustion. Moreover, for combustion to occur there are two essential elements. The first one is a fuel or a substance that releases energy and ignites, and the second one is an oxidant, which accepts electrons. This mix and reaction causes high temperatures and release of heat in the form of fire and flames.
This implies, that for fireballs or any other form of fire to exist there must be oxygen or any substance that replaces it. This does not occur in space because the levels of oxygen are extremely low, this means, at least oxygen is added fireballs are not possible in this context as there is no oxygen, and therefore no combustion (Option C).
The the precipitate : Al(OH)₃(s)
The spectator ions : 3Cl⁻ and 3K⁺
<h3>Further explanation</h3>
Reaction
AlCl₃ + 3KOH → Al(OH)₃ + 3KCl
From solubility rules :
Compounds of OH− are insoluble except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺ , Sr²⁺, and Ba²⁺
Compounds of Cl−, Br−, I− are soluble except Ag⁺, Hg₂²⁺, Pb²⁺
So the the precipitate : Al(OH)₃(s)
net ionic reaction
AlCl₃ + 3KOH → Al(OH)₃ + 3KCl
Al³⁻+3Cl⁻+3K⁺+3OH⁻⇒Al(OH)₃(s)+3K⁺+3Cl⁻
Remove the spectator : 3Cl⁻ and 3K⁺
Al³⁻(aq)+3OH⁻(aq)⇒Al(OH)₃(s)