Answer:
18.22874999999973
I recommend you to round the nearest 1 d.p
Explanation:
<em>h</em><em>a</em><em>v</em><em>e</em><em> </em><em>a</em><em> </em><em>g</em><em>r</em><em>e</em><em>a</em><em>t</em><em> </em><em>d</em><em>a</em><em>y</em><em>!</em>
Answer:
Element 1
Explanation:
The ionization energy is defined as the energy required to remove electrons from the atoms.
We know that the nucleus of the atom attracts the electrons, thus, bound these electrons to the atom.
This means that as the radius decreases, the force of attraction between the nucleus and the electron will increase, therefore, the energy required to remove the electron would increase (and vice-versa).
Based on the above, the atom with the smallest radius would be the atom with the largest first ionization energy.
Hope this help :)
Answer:
covalent bonding becaus of there both non metals
The reduction reaction is the gain of electrons while oxidation reaction is the loss of electrons. For potassium ion(K+), the reaction should be K+ + e- ==> K. So the answer is (1).
Answer:
1.25 moles of tungsten carbide
Explanation:
Tungsten carbide, WC, is a substance that is produced prom carbon and tungsten as follows:
W + C → WC
Based on the reaction, 1 mole of Carbon produce 1 mole of tungsten carbide. That means if 1.25 moles of carbon are added in excess of tungsten, the moles of tungsten carbide produced are:
<h3>1.25 moles of tungsten carbide</h3>
