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viktelen [127]
3 years ago
12

Are two atoms of the same element identical

Chemistry
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

Yes

Explanation:

Atoms of the same element consist of the same atomic number that is number of protons or electrons and different mass number that is number of neutrons. This variation or change in the number of neutrons in an atom gives rise to different isotopes of an element. An element with different isotopes occurs in nature

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Which of the following covalent bonds is the most polar?
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Answer:

D.) H-O

Explanation:

Polarity is determined based on the difference in electronegativity of the atoms. The greater the difference, the more polar the bond. The general trend is that the atoms in the top-right corner of the periodic table are the most electronegative.

A.) is incorrect because H-H has no electronegativity difference, making it nonpolar.

B.) and C.) are incorrect because their electronegativity differences are not the greatest.

D.) is correct because the electronegativity difference between the H and O is the greatest.

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If 200 grams of water is to be heated from 24.0° C to 100.0° C to make a cup of tea, how much heat must be added?
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What is the Bayer process explain it
Vlada [557]

Answer:

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3 years ago
Why is ocean water more dense than freshwater
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Hope this helps good luck on ur examsss :))))
8 0
3 years ago
How many milliliters of 0.125 M FeCl3 are needed to react with an excess of Na2S to produce 3.75 g of Fe2S3 if the percent yield
Katyanochek1 [597]

Answer:

0.912 mL

Explanation:

3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)

FeCl3 is the limiting reactant.

Number of moles of iron III sulphide produced= 3.75g/87.92 g/mol = 0.043 moles

Hence actual yield of Iron III sulphide = 0.043 moles

Theoretical yield of Iron III sulphide = actual yield ×100%/ %yield

Theoretical yield of iron III sulphide= 0.043 ×100/75 = 0.057 moles of Iron III sulphide

From the reaction equation,

2moles of iron III chloride produced 1 mole of iron III sulphide

x moles of iron III chloride, will produce 0.057 of iron III sulphide

x= 2× 0.057= 0.114 moles of iron III chloride

But

Volume= number of moles/ concentration

Volume= 0.114/0.125

Volume= 0.912 mL

4 0
3 years ago
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