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Dovator [93]
10 months ago
9

stearic acid and linoleic acid stearic acid and linoleic acid stearic acid has the higher melting point, because it has two more

methylene groups (giving it a greater surface area and therefore more intermolecular van der waals interactions) than linoleic acid.
Chemistry
1 answer:
elena55 [62]10 months ago
4 0

Acid palmitic acid has higher melting point, because it has two more methylene groups.

\text { Myristic acid } \rightarrow \mathrm{CH}_3\left(\mathrm{CH}_2\right)_{12} \mathrm{COOH} \\& \text { Palmitic acid } \rightarrow \mathrm{CH}_3\left(\mathrm{CH}_2\right)_{14} \mathrm{COOH} \\

Acid palmitic acid has higher melting point, because it has two more methylene groups.

Giving it a greater surface area and therefore more intermolecular  van der waals interact than the myristic acid.

stearic arid \mathrm{CH}_3\left(\mathrm{CH}_2\right)_{16} \mathrm{COOH}

linoleic acid \mathrm{C}_{18} \mathrm{H}_{32} \mathrm{O}_2 (two double bond)

Stearic acid has higher Melting point, because it does not have any Carbon-Carbon double bonds, whereas linoleic acid has two cis double bonds which prevent the molecules from packing closely together.

Oleic Acid and Linoleic acid.

\mathrm{C}_{18} \mathrm{H}_{34} \mathrm{O}_2-one double bond (cis)

Acid palmitic acid has higher melting point, because it has two more methylene groups.

For more such question on methylene group.

brainly.com/question/4279223

#SPJ4

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3 years ago
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<h3>What is emitting of energy, by electron?</h3>

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5 0
1 year ago
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8 0
3 years ago
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What mass of H2 is needed to react with 8.75 g of O2 according to the following equation: O2(g) + H2(g) → H2O(g)?
alina1380 [7]

Mass of H₂ needed to react with O₂ : 1.092 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

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\tt \dfrac{8.75}{32}=0.273

From the equation, mol ratio of O₂ : H₂ = 1 : 2, so mol H₂ :

\tt \dfrac{2}{1}\times 0.273=0.546

Mass H₂ (MW=2 g/mol) :

\tt 0.546\times 2=1.092~g

4 0
2 years ago
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Answer:

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vol. of water to add= 17.5 - 10 = 7.5L

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