By working backwards,
<span>you get 76 as your answer because you have to remove the rightmost digit, right? so the three-digit number is </span>
<span>76x </span>
<span>(x stands for the rightmost digit, because we don't know what the rightmost digit is) </span>
<span>we are told we have to add six to the three digit number to get 76x, so we have to subtract 6 from 76x: </span>
<span>76x - 6 = ??? </span>
<span>since we assume that the original two-digit number is NOT 76, and any number from 760 to 765 inclusive minus 6 is logically in the 750-range, we can conclude that the original two-digit number is 75. </span>
Answer:
506
Step-by-step explanation:
Following PEMDAS you'd start with your exponent
8^3-9×2÷3
Then you'd move on to multiplication
512-9×2÷3
Then do the division
512-18÷3
Then finish the problem by subtracting these two
512-6
We are told that f(x) = x + 2. We want to find .
Squaring f(x) on one side means we square x + 2 on the other.
So,
f(x) = x + 2
(f(x))² = (x + 2)²
= (x + 2)(x + 2)
We can use FOIL to square x + 2. The first terms multiply to x², the outside terms to 2x, the inside terms to 2x and the last terms to 4.
= x² + 2x + 2x + 4
= x² + 4x + 4
So [f(x)]² = x² + 4x + 4
ummm there's nothing attached
The answer is <span>π8^2 or about 201.06</span>