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vivado [14]
3 years ago
13

If five cards are dealt from a standard deck of cards, how many different ways can three diamonds and two non-diamonds be dealt

Mathematics
1 answer:
charle [14.2K]3 years ago
8 0
In a standard deck of cards, there are 13 diamond cards and 39 non diamonds. To choose 3 diamonds from 13 cards would be equivalent to 13*12*11 as there are less cards to choose from each time you remove a card. To choose two non diamonds from the other non diamonds cards would be equivalent to 39*38, taking into account the number of cards you remove each time you pick out one card. Hence the total number of ways is 13x12x11x39x38.
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kaheart [24]

Hello from MrBillDoesMath!

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Discussion:

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26 = (1/2) b (5b-7).  Multiply both sides by 2:

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52 = b(5b-7)  =>

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5b^2 - 7b - 52 = 0.   This factors as follows:

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