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vivado [14]
4 years ago
13

If five cards are dealt from a standard deck of cards, how many different ways can three diamonds and two non-diamonds be dealt

Mathematics
1 answer:
charle [14.2K]4 years ago
8 0
In a standard deck of cards, there are 13 diamond cards and 39 non diamonds. To choose 3 diamonds from 13 cards would be equivalent to 13*12*11 as there are less cards to choose from each time you remove a card. To choose two non diamonds from the other non diamonds cards would be equivalent to 39*38, taking into account the number of cards you remove each time you pick out one card. Hence the total number of ways is 13x12x11x39x38.
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Answer:

34

Step-by-step explanation:

x=3+√8

y =3-√8

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1/x^2+1/y^2

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= [(3-√8)²+(3+√8)²] / (3+√8)²(3-√8)²            [L.C.M  = (3+√8)²(3-√8)² ]

=[(3-√8+3+√8)²-2(3-√8)(3+√8) ] / [(3+√8)(3-√8)]²  

=[6²-2.(3²-√8² )] / (3²-√8²)²                 [ a²+ b²=(a+b)²-2ab]

=[36-2(9-8) ]/ (9-8)²

=[36-2.1] / 1²

=34

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Step-by-step explanation:

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