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Oksi-84 [34.3K]
3 years ago
8

Explain an example of how energy is transferred from one form to another

Physics
1 answer:
scoray [572]3 years ago
6 0

Answer:

read the explanation

Explanation:

Purchased electricity is fed into our TVs and is converted to light and sound.

Electricity goes into an electric bulb and is converted to visible light and heat energy.

Chemical Energy is converted to Electrical Energy (stove)

Chemical food energy is converted to Energy to Work (person running).

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Use the fact that the speed of light in a vacuum is about 3.00 × 108 m/s to determine how many kilometers a pulse from a laser b
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Read 2 more answers
Approximately, What is the value of the Hubble Constant, as measured by scientists? Hypothetically, if the value of the Hubble C
Serhud [2]

Answer:

The current value of the Hubble's constant = 73 km/sec/Mpc.

t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc

Explanation:

The current value of the Hubble's constant = 73 km/sec/Mpc. However, recent discoveries in the cosmology contradicts the idea of Hubble constant as being fixed. Some scientists are not agreeing on this value and the debate is going on.

Hubble law states that how fast universe is expanding or in other words, galaxies are expanding separating with a speed directly proportional to the distance of galaxies to the earth.

Hence,

v is directly proportional to d

where, v = apparent velocity

d = distance

if we equate velocity and distance then there comes Hubble constant.

v = H_{0} x d

 H_{0} = 73 km/sec/Mpc

where, Mpc = Mega Parsec = 1 Mpc = 3.086 x 10^{19} km      

We can use Hubble constant to tell the age of universe.

t = d/v

t = d/( H_{0} xd)

t = 1/H_{0}

Scientist calculated the age of universe by using Hubble constant, which is 13.4 billion years.

Now, if we hypothetically change the value of Hubble constant,

from H_{0} = 73 km/sec/Mpc to H_{0} = 700 km/sec/Mpc

then the age of universe will be:

t = 1/H_{0}

first convert the units of new H_{0} into 1/s

H_{0} = (700) x (/3.08 x 10^{19} )

H_{0} = 227.27 x10^{-19}  = 2.27 x 10^{-21} 1/s

So,

Age of universe will be:

t = 1/H_{0} = 1/2.27x10^{-21} 1/s

t = 2.27 x 10^{21} s

t = 71.9 trillion years

t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc

       

6 0
3 years ago
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