Are there any options or is it not multiple choice.
We are given the equation:
<span>x = 11t^2
</span>
We use that equation to calculate for the distance traveled.
For (a)
At t=2.20 sec,
x =53.24 meters
At t=2.95 sec,
x =95.73 meters
Velocity = (95.73 meters - 53.24<span> meters) / (2.95 s - 2.20 s ) = 56.65 m/s
</span>For (b)
At t=2.20 sec,
x =53.24 meters
At t=2.40 sec,
x =63.36 meters
Velocity = (63.36 meters - 53.24<span> meters) / (2.40 s - 2.20 s ) = 50.6 m/s</span>
In statistics there are different types of distributions, like rectangular, or Poisson, A normal distribution is bellshaped
When you put that into a Punnett square you first use the FOIL method because this is a dihybrid case where two traits are considered. This will be the resulting Punnett square:
PL Pl pL pl
PL PPLL PPLl PpLL PpLl
Pl PPLl PPll PpLl Ppll
pL PpLL PpLl ppLL ppLl
pl PpLl Ppll ppLl ppll
Now based on the Punnett square above, you can get the ratio. Remember that the dominant trait will always be expressed when you count phenotype combinations so as long as there is a capital letter in the combination, it will always be the one expressed.
So there are 9 polka dot, long eyelashes(PL), 3 polka dot, short eyelashes (Pl), 3 solid color, long eyelashes (pL), 1 solid short eyelashes(pl).
So your answer is D. 9:3:3:1 ratio
Answer:
The definition of that same given problem is outlined in the following section on the clarification.
Explanation:
The Q seems to be endless (hardly any R on the circuit). So energy equations to describe and forth through the inducer as well as the condenser.
Presently take a gander at the energy stored in your condensers while charging is Q.
⇒ 
So conclude C doesn't change substantially as well as,
When,
⇒ 
⇒ 
And therefore only half of the population power generation remains in the condenser that tends to leave this same inductor energy at 3/4 U.
