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3 years ago

13

Do simple sugars provide short term energy?

2 answers:

grandymaker [24]3 years ago

8 0

Simple<span> carbohydrates or </span>simple sugars<span> - These carbs are broken down and digested very quickly, but most </span>simple<span> carbs contain refined </span>sugars<span> and very few essential vitamins and minerals. Examples include table </span>sugar<span>, fruit juice, milk, yogurt, honey, molasses, maple syrup and brown </span>sugar<span>.</span>

zalisa [80]3 years ago

3 0

Yes,Sodium and Cholesterol in sugar provides Short amounts of energy to the human body. ✌

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5. Why might it be useful to determine the elements that a planet or moon is made up of?

exis [7]

because we will know more about out solar system

3 0

3 years ago

Read 2 more answers

Suppose you have a 0.750-kg object on a horizontal surface connected to a spring that has a force constant of 150 N/m. There is

marshall27 [118]

Answer:

$x=0.0049\ m= 4.9\ mm$

$d=0.01153\ m=11.53\ mm$

Explanation:

Given:

mass of the object, $m=0.75\ kg$

elastic constant of the connected spring, $k=150\ N.m^{-1}$

coefficient of static friction between the object and the surface, $\mu_s=0.1$

(a)

Let x be the maximum distance of stretch without moving the mass.

<em>The spring can be stretched up to the limiting frictional force 'f' till the body is stationary.</em>

$f=k.x$

$\mu_s.N=k.x$

where:

N = m.g = the normal reaction force acting on the body under steady state.

$0.1\times (9.8\times 0.75)=150\times x$

$x=0.0049\ m= 4.9\ mm$

(b)

Now, according to the question:

Amplitude of oscillation, $A= 0.0098\ m$

coefficient of kinetic friction between the object and the surface, $\mu_k=0.085$

Let d be the total distance the object travels before stopping.

<em>Now, the energy stored in the spring due to vibration of amplitude:</em>

$U=\frac{1}{2} k.A^2$

<u><em>This energy will be equal to the work done by the kinetic friction to stop it.</em></u>

$U=F_k.d$

$\frac{1}{2} k.A^2=\mu_k.N.d$

$0.5\times 150\times 0.0098^2=0.0850 \times 0.75\times 9.8\times d$

$d=0.01153\ m=11.53\ mm$

<em>is the total distance does it travel before stopping.</em>

7 0

2 years ago

A student squeezes a clothespin 82 times in a minute. Then, using the same hand and the same clothespin, he squeezes the clothes

tia_tia [17]

Could have gotten tired after the first trial. ? i’m not sure if that’s it

3 0

2 years ago

A gazelle leaps from a cliff 2.5 m high with a speed of 5.6m/s.

jeyben [28]

Initial speed of Gazelle is along x direction and its value will be

$v_x = 5.6 m/s$

also its initial height is given as

$y = 2.5 m$

Part a)

now from kinematics along Y direction

$\Delta y = v_y t + \frac{1}{2} at^2$

as we know that

$\Delta y = 0$

$v_y = 0$

$a = 9.8 m/s^2$

$2.5 = 0 + \frac{1}{2} (9.8) t^2$

$t = 0.714 s$

Part b)

distance moved horizontally

$\Delta x = v_x t$

as we know that

$v_x = 5.6 m/s$

now we will have

$v_x = 5.6 (0.714) = 4m$

so it will lend at distance of 4 m.

Part c)

final velocity in vertical direction

$v_{fy} = v_y + at$

$v_{fy} = 0 + (9.8)(0.714) = 7 m/s$

$v_x = 5.6 m/s$

so net speed will be

$v^2 = v_x^2 + v_y^2$

$v^2 = 7^2 + 5.6^2$

$v = 8.96 m/s$

7 0

3 years ago

Make the following prefix conversions.<br> 0.001s =ms

Free_Kalibri [48]

Answer:

To convert a millisecond measurement to a second measurement, divide the time by the conversion ratio. The time in seconds is equal to the milliseconds divided by 1,000.

Explanation:

hope it helps

4 0

2 years ago