The incorrect answer is C
Answer:38.66 m
Explanation:
Given
launch angle 
launch velocity 
center of mass continue to travel its original Path so it center of mass will be at a distance of



Center of mass will be at 
(b)if one of the piece will be at x=26 m then other will be at




Answer:
Explanation:
Given
Lowest four resonance frequencies are given with magnitude
50,100,150 and 200 Hz
The frequency of vibrating string is given by

where n=1,2,3 or ...n
L=Length of string
T=Tension
Mass per unit length
When string is clamped at mid-point
Effecting length becomes 
Thus new Frequency becomes

i.e. New frequency is double of old
so new lowest four resonant frequencies are 100,200,300 and 400 Hz
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