Answer:
Bounce 1 , pass 3, emb2
Explanation:
(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle. So it is Bounce1, pass3, emb2.
Answer:
1.6s
Explanation:
Given that A 1.20 kg solid ball of radius 40 cm rolls down a 5.20 m long incline of 25 degrees. Ignoring any loss due to friction,
To know how fast the ball will roll when it reaches the bottom of the incline, we need to calculate the acceleration at which it is rolling.
Since the frictional force is negligible, at the top of the incline plane, the potential energy = mgh
Where h = 5.2sin25
h = 2.2 m
P.E = 1.2 × 9.8 × 2.2
P.E = 25.84 j
At the bottom, K.E = P.E
1/2mv^2 = 25.84
Substitutes mass into the formula
1.2 × V^2 = 51.69
V^2 = 51.69/1.2
V^2 = 43.07
V = 6.56 m/s
Using the third equation of motion
V^2 = U^2 + 2as
Since the object started from rest,
U = 0
6.56^2 = 2 × a × 5.2
43.07 = 10.4a
a = 43.07/10.4
a = 4.14 m/s^2
Using the first equation of motion,
V = U + at
Where U = 0
6.56 = 4.14t
t = 6.56/4.14
t = 1.58s
Therefore, the time the ball rolls when it reaches the bottom of the incline is approximately 1.6s
Answer:
a) Image attached
b) It is acting CW
c) τ = 0.294N.m
Explanation:
As you can see in the image, the ruler will rotate clockwise.
For the total torque: τ = -W*(0.5 - 0.35) The distance used is from 35cm to 50cm
τ = -0.294N.m The magnitude is therefore: 0.294N
Answer:
A: Sunlight contains ultraviolet waves only.
Explanation:
Hopefully this helps!
The highest frequency (f) at which the source can operate is given as:
f = 55.133Hz.
<h3>What are sinusoidal waves?</h3>
The most realistic representation of how many objects in nature change state is a sine wave or sinusoidal wave.
A sine wave depicts how the intensity of a variable varies over time.
<h3>What is the calculation justifying the above result?</h3>
P = (1/2) μω²A²v
300W = 1/2 (4 X 10⁻²kg/m) ω₂ (0.05m)²v
Thus the wave speed is:
v = √(T/μ)
= √[(100N)/(4 X 10⁻²kg/m)
= 50m/s
300W = 1/2(4 X 10⁻²kg/m) ω²(0.05m)² (50m/s)
⇒ ω = 346.41 1/s
ω = 346.41 1/s
= 2πf
⇒ f = 55.133Hz
Learn more about Sinusoidal waves:
brainly.com/question/20912200
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