The resistance of the thermometer at room temperature is 15.04 ohms.
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<h3>What is a resistance thermometer?</h3>
A resistance thermometer is a type of thermometer that measures temperature through a change in resistance.
To calculate the resistance of the thermometer at room temperature, we use the formula below.
Formula:
- 100/27 = 2/(x-14.5)..............Eqquation 1
Where:
- x = Resistance of the thermometer at room temperature
Make x the subject of the equation
- x = [(27×2)/100]+14.5
- x = (54/100)+14.5
- x = 0.54+14.5
- x = 15.04 ohms.
Hence, The resistance of the thermometer at room temperature is 15.04 ohms.
Learn more about thermometers here: brainly.com/question/1531442
Answer:
the electroscope separate by the presence of charge carriers
Explanation:
Metal bodies are characterized by having free (mobile) electrons. In the electroscope the plates are in balance; when the external metal ball is touched, a charge is introduced into the device, when the body that touched the ball is separated, an excess charge remains. This charge, being a metal, is distributed over the entire surface, giving a uniform density and an electric force of repulsion is created between the two charged sheets, which tends to separate the sheets. This force is counteracted by the tension component as the sheets are separated at a given angle, the separation reaches the point where
Fe - Tx = 0
Fe = Tx
In summary, the electroscope separate its leaves by the presence of charge carriers
Explanation:
(a) The given figure is a convex lens.
(b) In this figure, the object is placed between F and optical center of a lens. Convex lens is a converging lens. It converges the beam of light falling on it after reflection. The image is formed on the same side of the lens as the object.
The formed image is enlarged and it is virtual and erect.
(i) Type : virtual
(ii) Orientation : upright
(iii) Size : Enlarged
Answer:
5 is the tripoid stand
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Answer:
540C.
Explanation:
A capacitor of capacitance C when charged to a voltage of V will have a charge Q given as follows;
Q = CV ----------(i)
From the question, the initial charge on the capacitor is the charge on it before it was connected to the resistor. In other words, the initial charge on the capacitor will have a maximum value which can be calculated using equation (i) above.
Where;
C = 6F
V = 90V
Substitute these values into equation (i) as follows;
Q = 6 x 90
Q = 540 C
Therefore, the initial charge on the capacitor is 540C.
