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3 years ago

11

A motorist driving at 25 meters/second decelerates to

2 answers:

Ilia_Sergeevich [38]3 years ago

8 0

Work done = 0.5*m*[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.

Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,

Work done = 0.5 * 1.50 x 10^3 * ((-15)^2 - 25^2) = 3 x 10^5 joules

Just ignore the negative value for the final result because work is a scalar quantity.

andrew11 [14]3 years ago

3 0

Answer:

C.

3.0 × 10^5 joules

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