Wouldn't you use sin, cos, tan?
<h2> (1 ,2) (2,-3)</h2><h2>(x1,y1) (x2, y2)</h2>
<h2> Distance formual</h2>
<h2> √(x2-x1)^+(y2-y1)^</h2>
<h2>= √(2-1)^+(-3-2)^</h2><h2>= √(1)^+(-5)^ [here square root and </h2><h2> square get cancelled]</h2><h2>= (1)+(-5)</h2><h2>= 1-5</h2><h2>= - 4</h2>
Answer: an arithmetic sequence
Step-by-step explanation:
1) 0.4
2)0.875
i dont know the 3 and 4 one
