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Ierofanga [76]
3 years ago
11

Suppose that 9 green balls and 14 purple balls are placed in an urn.  Two balls are then drawn in succession.  What is the proba

bility that the second ball drawn is a purple ball if the first ball is replaced before the second is drawn?
Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0
<span>14/23, or approximately 60.87% Since the first ball is replaced before the second is drawn, the two events are independent. And the probability of the second ball being purple is the percentage of the balls that are purple in the urn. The total number of balls is 9+14 = 23 and 14 of those balls are purple, so 14/23 = probability of the second ball drawn being purple. It's approximately 0.608695652, or 60.87%</span>
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GenaCL600 [577]
3.14(3^2 +3(4)
3.14(9+12)
3.14(21)
65.94
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3 years ago
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A sample of n = 5 scores has a mean of m = 8. one new score is added to the sample and the new mean is calculated to be m = 9. w
Yuri [45]
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Una torre de 28.2 m de altura esta situada a la orilla de un rio, desde lo alto del edificio el ángulo de depresión a la orilla
Svet_ta [14]

Answer:

El ancho del río es 59.9 metros.

Step-by-step explanation:

El ancho del río lo podemos calcular con la siguiente relación trigonométrica asumiendo que la torre forma un triángulo rectángulo con el río:

tan(\theta) = \frac{CO}{CA}

En donde:

CA: es el cateto adyacente = Altura de la torre = 28.2 m

CO: es el cateto opuesto = ancho del río =?

θ: es el ángulo adyacente a CA

Dado que el ángulo de depresión (25.2°) está ubicado fuera de la parte superior de la hipotenusa del triángulo que forma la torre con la orilla opuesta del río, debemos calcular el ángulo interno (θ) como sigue:

\theta = (90 - 25.2)^{\circ} = 64.8 ^{\circ}

Ahora, el ancho del río es:

CO = tan(\alpha)*CA = tan(64.8)*28.2 = 59.9 m

Por lo tanto, el ancho del río es 59.9 metros.

Espero que te sea de utilidad!                  

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2 years ago
Help me please<br> thx so much<br> have a good one
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