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Ierofanga [76]
4 years ago
11

Suppose that 9 green balls and 14 purple balls are placed in an urn.  Two balls are then drawn in succession.  What is the proba

bility that the second ball drawn is a purple ball if the first ball is replaced before the second is drawn?
Mathematics
1 answer:
Hitman42 [59]4 years ago
8 0
<span>14/23, or approximately 60.87% Since the first ball is replaced before the second is drawn, the two events are independent. And the probability of the second ball being purple is the percentage of the balls that are purple in the urn. The total number of balls is 9+14 = 23 and 14 of those balls are purple, so 14/23 = probability of the second ball drawn being purple. It's approximately 0.608695652, or 60.87%</span>
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3 years ago
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3 years ago
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3 years ago
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The remainder obtained when 3x^3 - 6x^2 + ax -1 is divided by x+1 is equal to the remainder obtained when the same expression is
telo118 [61]

Answer:

5a

Step-by-step explanation:

Solution

verified

Verified by Toppr

We have x

3

−ax

2

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Apply remainder theorem

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x=a

Put x=a in equation.

(a)

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3

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=6a−a

=5a

Then reminder is 5a

4 0
3 years ago
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