How many times greater is the value of the digit 5 in 853,607 than the value of the digit 5 in 362,051.

A basket ball player made 23 out of 50 free throws in the last game. What percent of the free throws did he make?

AlexFokin [52]

23/50 times 100= 46%

4 0

3 years ago

Brooke is making dish towels for the kitchen. If each towel uses 2 2/3 feet of fabric and she is making 8 towels, how much fabri

Julli [10]

$2 \frac{2}{3} \times 8 = 8 \times \frac{2}{3}$
$= \frac{16}{3} = 5 \frac{1}{3 } + 16 = 21 \frac{1}{3}$
Answer is 21
$\frac{1}{3}$

3 0

3 years ago

Use the row of numbers shown below to generate 12 random numbers between 01 and 99.

sattari [20]

Answer:

Below is the complete step-by-step explanation.

Step-by-step explanation:

Given the row of numbers

25060 12315 86244 97348 36173 32710 80033 16160

Taking 25060 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (25060) into your calculator. 25060 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

85 90 62 45 26 97 40 55 67 17 10 32

Taking 12315 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (12315) into your calculator. 12315 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

33 20 26 68 73 09 46 14 82 74 17 04

Taking 86244 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (86244) into your calculator. 86244 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

54 93 02 50 37 01 86 51 38 28 23 36

Taking 97348 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (97348) into your calculator. 97348 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

04 79 01 86 51 02 50 37 38 28 23 36

Taking 36173 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (36173) into your calculator. 36173 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

13 03 28 17 14 31 98 47 40 48 68 19

Taking 32710 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (32710) into your calculator. 32710 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

22 80 42 03 27 89 98 46 14 31 72 56

Taking 80033 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (80033) into your calculator. 80033 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

29 86 51 01 23 64 37 36 35 72 14 59

Taking 16160 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (16160) into your calculator. 16160 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

93 54 72 58 30 14 48 87 99 95 83 29

Keywords: random number generator

Learn more about random number generator from brainly.com/question/1601128

#learnwithBrainly

6 0

3 years ago

In the number 7725 which place contain digits where one digit is ten times as great as the other

Tcecarenko [31]

The 7s digit there you go

8 0

3 years ago

This shape is made using three semicircles The smaller semicircle have diameters of 10cm Calculate the shaded area Take 3.142 an

CaHeK987 [17]

Answer:

The shaded area is 314.2 cm²

Step-by-step explanation:

Here we have the diameter, d₁ of the smaller semicircles as 10 cm

We note that the larger semicircle is subtended (bounded) by the two smaller semicircles;

1 shaded small semicircle and the other is blank

Therefore, the diameter, d₂ of the large semicircle = 10 + 10 = 20 cm

Also the area of the shaded figure consists of the removal of one small semicircle and the addition of the other semicircle to the area of the larger semicircle such that the area of the shaded figure is as follows

Shaded area of figure = π·d₂²/4 + π·d₁²/4 - π·d₁²/4 = π·d₂²/4 = π×20²/4 = 100×3.142 = 314.2 cm²

Shaded area = 314.2 cm².

6 0

3 years ago