As I understand from your question, we should synthesize nickel sulfate first from nickel (II) oxide and sulfuric acid and second from nickel carbonate and sulfuric acid.
The chemical reactions will look like this:
NiO (s) + H₂SO₄ (aq) → NiSO₄ (aq) + H₂O (l)
NiCO₃ (aq)* + H₂SO₄ → NiSO₄ (aq) + H₂CO₃ (aq)
but carbonic acid will decompose to carbon dioxide and water
H₂CO₃ (aq) → CO₂ (g) + H₂O (l)
(*) NiCO₃ has a poor solubility in water, but enough to start the reaction.
Answer:
0.05 moles of sodium sulfate are required.
Explanation:
Concentration of sodium ions in 1 L = 0.10 M
Moles of sodium ions = 0.10 mol
1 mole of sodium sulfate gives 2 moles of sodium ions.
Then 0.10 mol of sodium ions will be given by:
0.05 moles of sodium sulfate are required.
Answer: -
Al₂O₃
Explanation: -
The atomic number of aluminium Al = 13
The electronic configuration of aluminium =2,8,3
To have 8 electrons in it's valence shell, it must lose 3 electrons.
So the valency of Al is +3.
The atomic number of oxygen is 8
The electronic configuration of O oxygen = 2,6
So to have 8 electrons in it's valence shell it must gain 2 electrons.
Thus the valency of O = -2.
The formula for aluminium oxide = Al ⁺³ O²⁻
= Al₂O₃