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adelina 88 [10]
3 years ago
12

A projectile is fired at an upward angle of 29.7° from the top of a 108-m-high cliff with a speed of 130-m/s. What will be its

speed (in m/s) when it strikes the ground below?
Physics
1 answer:
german3 years ago
5 0

Answer:

79.2 m/s

Explanation:

θ = angle at which projectile is launched = 29.7 deg

a = initial speed of launch = 130 m/s

Consider the motion along the vertical direction

v₀ = initial velocity along the vertical direction = a Sinθ = 130 Sin29.7 = 64.4 m/s

y = vertical displacement = - 108 m

a = acceleration = - 9.8 m/s²

v = final speed as it strikes the ground

Using the kinematics equation

v² = v₀² + 2 a y

v² = 64.4² + 2 (-9.8) (-108)

v = 79.2 m/s

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What will be the fundamental frequency and first three overtones for a 26cm long organ at 20°C if it is open ( at 20°C, the spee
kakasveta [241]

Explanation:

The frequency of an organ pipe if it is open is given by :

f=\dfrac{nv}{2l}

v is speed of sound in air is 343 m/s at 20°C

For fundamental frequency, n = 1

f=\dfrac{1\times 343}{2\times 0.26}\\\\f=659.61\ Hz

First overtone frequency,

f_1=2f\\\\f_1=2\times 659.61\\\\f_1=1319.22\ Hz

Second overtone frequency,

f_2=3f\\\\f_2=3\times 659.61\\\\f_2=1978.83\ Hz

Third overtone frequency

f_3=4f\\\\f_3=4\times 659.61\\\\f_3=2638.44\ Hz

Hence, this is the required solution.

3 0
3 years ago
When air pressure decreases, the mercury in a barometer _____.
siniylev [52]

Answer:

The mercury in the barometer will go down as there is less air pressing down on the bulb of the barometer to push mercury up.

Explanation:

7 0
3 years ago
The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5
nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

G\frac{mM}{R^2}=m\frac{v^2}{R}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant

m=11,100 kg is the mass of the telescope

M=5.97\cdot 10^{24} kg is the mass of the Earth

R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s

6 0
3 years ago
1. A wheel has a radius of 4.1 m. How far (path length) does a point on the wheel travel if the wheel is rotated through angles
Olin [163]

Answer:

<em>a) 2.15 m</em>

<em>b) 123 m</em>

<em>c) 772.8 m</em>

Explanation:

<u>Circular Motion</u>

One point located at a distance r from the center of rotation travels a distance L given by the arc length :

L= \theta r

Where \theta is the angle formed during the rotation.

The wheel described in the question has a radius r=4.1 m and a point on the wheel rotates some angles given in each part:

a) \theta=30^o=30\cdot \pi / 180=\pi/6 \ rad

Calculating L

L= \pi/6 \cdot 4.1=2.15 \ m

b) \theta=30\ rad

L= 30 \cdot 4.1=123 \ m

c) \theta = 30\ revolutions = 30\cdot 2\pi\ rad=60\pi \ rad

L= 60\pi \cdot 4.1=772.8 \ m

5 0
3 years ago
4. How long would it take for a water balloon to fall 39 m if we dropped it starting from rest down an
Paraphin [41]

Answer:

Around 2.8212 sec

Explanation:

Given the eqn x=1/2at^2+vot

your vo=0

39=1/2(-9.8)t^2

=7.95=t^2

=2.82sec

8 0
3 years ago
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