Answer:
352,088.37888Joules
Explanation:
Complete question;
A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.
A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)
Chane in potential energy is expressed as;
ΔGPH = mgΔH
m is the mass of the hiker
g is the acceleration due to gravity;
ΔH is the change in height
Given
m = 53kg
g = 9.8m/s²
ΔH = 2574-350 = 2224ft
since 1ft = 0.3048m
2224ft = (2224*0.3048)m = 677.8752m
Required
Gravitational potential energy
Substitute the values into the formula;
ΔGPH = mgΔH
ΔGPH = 53(9.8)(677.8752)
ΔGPH = 352,088.37888Joules
Hence the gravitational potential energy is 352,088.37888Joules
Answer:
Incident ray
Explanation:
"To describe the reflection of light, we will use the following terminology. The incoming light ray is called the incident ray. The light ray moving away from the surface is the reflected ray. The most important characteristic of these rays is their angles in relation to the reflecting surface."
https://www.siyavula.com/read/science/grade-11/geometrical-optics/05-geometrical-optics-03
<span>Fossils are the preserved remains or traces of animals, plants, and other organisms from the remote past. The totality of fossils, both discovered and undiscovered, and their placement in fossiliferous (fossil-containing) rock formations and sedimentary layers (strata) is known as the fossil record</span>
Answer:
90 C
Explanation:
Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,
I = dQ/dt
dQ = Idt
∫dQ = ∫Idt
Q = It................................ Equation 1
Where Q = amount of charge, I = current, t = time.
Given: I = 3.6 A, t = 25 s.
Substituting into equation 1,
Q = 3.6(25)
Q = 90 C.
Hence the amount of charge passing through the cross section of the conductor = 90 C
Answer:
Explanation:
Given
Time taken to reach ground is 
Malda initial velocity 
Let h be the height of Cliff
using 
where, u=initial velocity
t=time
In first case chirpy drop downward thus u=0
For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]
time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by
