The pressure of the gas = 40 atm
<h3>Further explanation</h3>Given
200 ml container
P = 2 atm
final volume = 10 ml
Required
Final pressure
Solution
Boyle's Law
At a fixed temperature, the gas volume is inversely proportional to the pressure applied
Input the value :
P₂ = P₁V₁/V₂
P₂ = 2 x 200 / 10
P₂ = 40 atm
Explanation:
The given data is as follows.
= 98.70 kPa = 98700 Pa,
T = = (30 + 273) K = 303 K
height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)
Density = 13.534 g/mL =
= 13534
The relation between pressure and atmospheric pressure is as follows.
P =
Putting the given values into the above formula as follows.
P =
=
= 102683.05 Pa
= 102.68 kPa
thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.