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frosja888 [35]
2 years ago
9

Eli states that sodium phosphate is a mixture because it is composed of both sodium ions and phosphate ions.

Chemistry
2 answers:
KonstantinChe [14]2 years ago
7 0

Answer is: c. It is incorrect because sodium phosphate is a compound that has a single composition.

Sodium phosphate is chemical compound composed of atoms connected with chemical bonds.

Pure substance is made of only one type of atom (element) or only one type of molecule (compound), it has definite and constant composition with distinct chemical properties.

Pure substances can be separated chemically, not physically, that is difference between pure substances and mixtures.

Veseljchak [2.6K]2 years ago
6 0
C is the answer just took the test
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Setler [38]
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5 0
2 years ago
Suppose 0.363 g of barium acetate is dissolved in 100. mL of a 25.0 m M aqueous solution of ammonium sulfate. Calculate the fina
sdas [7]

Answer:

Molarity of Ba²⁺ is 0M

Explanation:

Some barium ion, Ba²⁺ is produced when barium acetate is dissolved (Moles of barium acetate = moles of Ba²⁺ in solution). Then, Ba²⁺ reacts with sulfate ion to produce BaSO₄, an insoluble salt. The concentration of Ba²⁺ is the initial concentration - the concentration of SO₄²⁻ in solution.

Initial moles of Ba²⁺:

Moles barium acetate (Molar mass: 255.43g/mol)

0.363g * (1mol / 255.43) = 1.421x10⁻³ moles of Ba²⁺

Moles SO₄²⁻ = Moles of ammonium sulfate:

100mL = 0.100L * (0.025mol / L) = 2.5x10⁻³ moles of SO₄²⁻.

As moles of SO₄²⁻ are higher than moles of Ba²⁺, Molarity of Ba²⁺ is 0M because all moles of Ba²⁺ reacts producing BaSO₄(s), an insoluble salt.

5 0
3 years ago
Which option the answer plz
inysia [295]
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I'd say the answer you're looking for would be A) Such small amounts supply essential trace elements

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4 0
2 years ago
Read 2 more answers
Calculate the solubility of BaCO3 (a) in pure water and (b) in a solution in which [CO32-] = 0.289 M. Solubility in pure water =
jasenka [17]

Answer:

(a). The solubility of BaCO_{3} in pure water is 4.4\times10^{-5}\ M

(b). The solubility of BaCO_{3} in solution is 6.92\times10^{-9}\ M

Explanation:

Given that,

(a). The solubility of BaCO_{3} in pure water

(b). The solubility of BaCO_{3} in a solution

Solubility of CO_{3}^{-2} is 0.289 M

We know that,

The solubility product constant  of  BaCO_{3} is 2\times10^{-9}

Let the solubility of BaCO_{3} is s.

We need to calculate the solubility of BaCO_{3} in pure water

Using formula of solubility

ksp=s\times s

ksp=s^2

s=\sqrt{ksp}

Put the value into the formula

s=\sqrt{2\times10^{-9}}

s=4.4\times10^{-5}\ M

(b). We need to calculate the solubility of BaCO_{3} in solution

Using formula of solubility

ksp=s\times s

Put the value into the formula

2\times10^{-9}=s\times 0.289

s=\dfrac{2\times10^{-9}}{0.289}

s=6.92\times10^{-9}\ M

Hence, (a). The solubility of BaCO_{3} in pure water is 4.4\times10^{-5}\ M

(b). The solubility of BaCO_{3} in solution is 6.92\times10^{-9}\ M

3 0
3 years ago
a piece of ribbon is shared equally among 5 girls what fraction of the ribbon does each girl get, 20 points!!!!​
bulgar [2K]

Answer:

5 piece of ribbon

Explanation:

Because ther are a piece of ribbon is shade

5 0
3 years ago
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