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3 years ago

Eli states that sodium phosphate is a mixture because it is composed of both sodium ions and phosphate ions.

Chemistry

2 answers:

KonstantinChe [14]3 years ago

7 0

Answer is: c. It is incorrect because sodium phosphate is a compound that has a single composition.

Sodium phosphate is chemical compound composed of atoms connected with chemical bonds.

Pure substance is made of only one type of atom (element) or only one type of molecule (compound), it has definite and constant composition with distinct chemical properties.

Pure substances can be separated chemically, not physically, that is difference between pure substances and mixtures.

Veseljchak [2.6K]3 years ago

6 0

C is the answer just took the test

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3 years ago

Which is and element A) Salad B) Sugar C) Water D) Potassium

Semenov [28]

Answer:

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4 years ago

Two posssible lewis structures for the molecule ch2s are given. determine the formal charge on each atom in both structures

jok3333 [9.3K]

The formal charge on each atom can be known by counting up the number of valence electrons that is present on each atom.

<h3>What is Lewis structure?</h3>

The term Lewis structure is the representation of a compound using its symbols and showing the valence electrons as dots. This question is incomplete as the Lewis structures were not shown.

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2 years ago

How many atoms are there in 5.10 moles of sulfur?

Alexxx [7]

1 mole ------------- 6.02 x 10²³ atoms
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3 0

3 years ago

Read 2 more answers

g Tibet (altitude above sea level is 29,028 ft) has an atmospheric pressure of 240. mm Hg. Calculate the boiling point of water

Marina CMI [18]

Answer: The boiling point of water in Tibet is 69.9°C

Explanation:

To calculate the boiling point of water in Tibet, we use the Clausius-Clayperon equation, which is:

$\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$P_1$ = initial pressure which is the pressure at normal boiling point = 1 atm = 760 mmHg (Conversion factor: 1 atm = 760 mmHg)

$P_2$ = final pressure = 240. mmHg

$\Delta H_{vap}$ = Heat of vaporization = 40.7 kJ/mol = 40700 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

$T_1$ = initial temperature or normal boiling point of water = $100^oC=[100+273]K=373K$

$T_2$ = final temperature = ?

Putting values in above equation, we get:

$\ln(\frac{240}{760})=\frac{40700J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{T_2}]\\\\-1.153=4895.36[\frac{T_2-373}{373T_2}]\\\\T_2=342.9K$

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

$T(K)=T(^oC)+273$

$342.9=T(^oC)+273\\T(^oC)=(342.9-273)=69.9^oC$

Hence, the boiling point of water in Tibet is 69.9°C

3 0

3 years ago